$activeQuery = MysqL_query("SELECT count(`status`) AS `active` FROM `assignments` WHERE `user` = $user_id AND `status` = 0");
$active = MysqL_fetch_assoc($activeQuery);
$FailedQuery = MysqL_query("SELECT count(`status`) AS `Failed` FROM `assignments` WHERE `user` = $user_id AND `status` = 1");
$Failed = MysqL_fetch_assoc($FailedQuery);
$completedQuery = MysqL_query("SELECT count(`status`) AS `completed` FROM `assignments` WHERE `user` = $user_id AND `status` = 2");
$completed = MysqL_fetch_assoc($completedQuery);
必须有更好的方法来做到这一点,对吧？我不知道我需要详细说明,因为你可以看到我正在尝试做什么,但有没有办法在一个查询中完成所有这些？我需要能够输出活动,失败和完成的分配,最好是在一个查询中.
最佳答案
您可以尝试这样的查询
原文链接：https://www.f2er.com/mysql/433694.htmlSELECT Status,COUNT(*) StatusCount
FROM assignments
WHERE Status IN (0,1,2)
AND User = $user_id
GROUP BY Status