我试图减去2个别名,以便创建另一个别名,但我得到一个“未知列”错误.
这是我的sql:
select o.id,o.name,(select sum(l.source_expense)
from `assignments` as a
left join `leads` as l on (l.id = a.lead_id)
where a.{$this->sql_column}=o.id
and l.date_created between {$this->date_from} and {$this->date_to}
and find_in_set(l.vertical_id,'".implode(',',$this->app_user->verticals)."')
) as `expense`,(select sum(a.buyer_revenue)
from `assignments` as a
left join `leads` as l on (l.id = a.lead_id)
where a.refunded=0
and a.{$this->sql_column}=o.id
and l.date_created between {$this->date_from} and {$this->date_to}
and find_in_set(l.vertical_id,$this->app_user->verticals)."')
) as `revenue`,`revenue` - `expense` as `profit`
from {$this->sql_table} as o
基本上,我想通过从费用中减去收入来创建利润别名.原因是我正在使用数据表并希望列可以排序.我已经知道我可以用PHP轻松做到这一点.
我怎么能做到这一点?
编辑 – 我尝试了下面的答案,并从PHPStorm获得“每个派生表应该有别名”错误,并在尝试运行查询时出现语法错误.
继承人新的查询:
select t.id,t.name,t.expense,t.revenue,t.revenue - t.expense as profit
from(select o.id,$this->app_user->verticals)."')
) as `revenue`
from {$this->sql_table} as o
) as t
最佳答案
只需用另一个select包装它,然后别名将可用于数学计算:
原文链接:https://www.f2er.com/mysql/432868.htmlSELECT t.id,t.revenue -t.expense as `profit`
FROM (Your Query Here) t