我有以下查询返回所有员工的薪水.这项工作完美但我需要收集额外的数据,我将聚合到一个单元格中(参见结果集2).
如何将数据聚合到逗号分隔列表中？有点像Sum所做的,但我需要一个字符串作为回报.
SELECT Employee.Id,SUM(Pay) as Salary FROM Employee INNER JOIN PayCheck ON PayCheck.EmployeeId = Employee.Id GROUP BY Employee.Id
结果集1
Employee.Id Salary
-----------------------------------
1 150
2 250
3 350
我需要：
结果集2
Employee.Id Salary Data
----------------------------------------------------
1 150 One,Two,Three
2 250 Four,Five,Six
3 350 Seven
解决方法
对于sql Server 2005,请使用STUFF函数和FOR XML PATH：
WITH summary_cte AS (
SELECT Employee.Id,SUM(Pay) as Salary
FROM Employee
JOIN PayCheck ON PayCheck.EmployeeId = Employee.Id
GROUP BY Employee.Id)
SELECT sc.id,sc.salary,STUFF((SELECT ','+ yt.data
FROM your_table yt
WHERE yt.id = sc.id
GROUP BY yt.data
FOR XML PATH(''),TYPE).value('.','VARCHAR(max)'),1,'')
FROM summary_cte sc
但是,您缺少有关要将数据转换为逗号分隔字符串的位置的详细信息,以及它与员工记录的关系…
