有两个字符串a和b
一个字符串包含逗号.我想用逗号分割一个字符串,然后遍历每个元素.
如果b字符串包含任何以逗号分割的元素将返回0
(例如：a =“4,6,8”; b =“R3799514”因为b字符串包含4所以返回0)
如何使用存储过程实现此目的？提前致谢！
我见过一个split函数：
CREATE FUNCTION dbo.Split(@String varchar(8000),@Delimiter char(1))
returns @temptable TABLE (items varchar(8000))
as
begin
declare @idx int
declare @slice varchar(8000)
select @idx = 1
if len(@String)<1 or @String is null return
while @idx!= 0
begin
set @idx = charindex(@Delimiter,@String)
if @idx!=0
set @slice = left(@String,@idx - 1)
else
set @slice = @String
if(len(@slice)>0)
insert into @temptable(Items) values(@slice)
set @String = right(@String,len(@String) - @idx)
if len(@String) = 0 break
end
return
end
select top 10 * from dbo.split('Chennai,Bangalore,Mumbai',',')
解决方法
以下将工作 –
DECLARE @A VARCHAR (100)= '4,5,6' DECLARE @B VARCHAR (100)= 'RXXXXXX' DECLARE @RETURN_VALUE BIT = 1 --DEFAULT 1 SELECT items INTO #STRINGS FROM dbo.split(@A,') IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CHARINDEX(items,@B) > 0) SET @RETURN_VALUE = 0 PRINT @RETURN_VALUE DROP TABLE #STRINGS
IF EXISTS(SELECT 1 FROM #STRINGS S WHERE CONTAINS(items,@B)) SET @RETURN_VALUE = 0
