我必须在toad中编写一个Oracle查询来查找字符串中所有出现的字符.例如,如果我在字符串SSSRNNSRSSR中搜索R,它应该返回位置4,8和11.
我是Oracle新手并试过这个.
select instr(mtr_ctrl_flags,'R',pos + 1,1) as pos1 from mer_trans_reject where pos in ( select instr(mtr_ctrl_flags,1,1) as pos from mer_trans_reject );
其中mtr_ctrl_flags是列名.我收到错误,表明pos是无效的标识符.
解决方法
扩展GolezTrol的答案,您可以使用正则表达式来显着减少您执行的递归查询的数量:
select instr('SSSRNNSRSSR',level) from dual connect by level <= regexp_count('SSSRNNSRSSR','R')
REGEXP_COUNT()返回模式匹配的次数,在这种情况下是SS在SSSRNNSRSSR中存在的次数.这会将递归级别限制为您需要的确切数字.
INSTR()只是在你的字符串中搜索R的索引. level是递归的深度,但在这种情况下,它也是字符串出现的级别,因为我们限制了所需的递归次数.
如果您想要选择的字符串更复杂,那么您可以使用正则表达式ans REGEXP_INSTR()而不是INSTR()但它会更慢(不是太多)并且除非需要,否则它是不必要的.
所要求的简单基准:
两个CONNECT BY解决方案将指示使用REGEXP_COUNT对此大小的字符串快20%.
sql> set timing on sql> sql> -- CONNECT BY with REGEX sql> declare 2 type t__num is table of number index by binary_integer; 3 t_num t__num; 4 begin 5 for i in 1 .. 100000 loop 6 select instr('SSSRNNSRSSR',level) 7 bulk collect into t_num 8 from dual 9 connect by level <= regexp_count('SSSRNNSRSSR','R') 10 ; 11 end loop; 12 end; 13 / PL/sql procedure successfully completed. Elapsed: 00:00:03.94 sql> sql> -- CONNECT BY with filter sql> declare 2 type t__num is table of number index by binary_integer; 3 t_num t__num; 4 begin 5 for i in 1 .. 100000 loop 6 select pos 7 bulk collect into t_num 8 from ( select substr('SSSRNNSRSSR',level,1) as character 9,level as pos 10 from dual t 11 connect by level <= length('SSSRNNSRSSR') ) 12 where character = 'R' 13 ; 14 end loop; 15 end; 16 / PL/sql procedure successfully completed. Elapsed: 00:00:04.80
流水线表函数有点慢,但看看它如何在具有大量匹配的大字符串上执行会很有趣.
sql> -- PIPELINED TABLE FUNCTION sql> declare 2 type t__num is table of number index by binary_integer; 3 t_num t__num; 4 begin 5 for i in 1 .. 100000 loop 6 select * 7 bulk collect into t_num 8 from table(string_indexes('SSSRNNSRSSR','R')) 9 ; 10 end loop; 11 end; 12 / PL/sql procedure successfully completed. Elapsed: 00:00:06.54