sql语句的哈希值

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当我们在Oracle中执行任何sql语句时,会为该sql语句分配一个哈希值并将其存储到库缓存中.因此,稍后,如果另一个用户请求相同的查询,则Oracle会找到哈希值并执行相同的执行计划.但是,我对哈希值有一个疑问.我的意思是,哈希值是如何生成的?我的意思是,Oracle服务器是使用某些算法还是只是将sql字符串转换为某个数值.

从那时起,我正在阅读Pro Oracle sql书籍,上面写着,

select * from employees where department_id = 60;

SELECT * FROM EMPLOYEES WHERE DEPARTMENT_ID = 60;

select /* a_comment */ * from employees where department_id = 60;

将返回不同的哈希值,因为当执行sql语句时,Oracle首先将字符串转换为哈希值.但是,当我尝试这个时,它返回相同的哈希值.

sql> select * from boats where bid=10;

no rows selected


Execution Plan
----------------------------------------------------------
Plan hash value: 2799518614

-------------------------------------------------------------------------------------
| Id  | Operation                   | Name  | Rows  | Bytes | Cost (%cpu)| Time     |
-------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT            |       |     1 |    16 |     1   (0)| 00:00:01 |
|   1 |  TABLE ACCESS BY INDEX ROWID| BOATS |     1 |    16 |     1   (0)| 00:00:01 |
|*  2 |   INDEX UNIQUE SCAN         | B_PK  |     1 |       |     0   (0)| 00:00:01 |
-------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   2 - access("BID"=10)

sql> SELECT * FROM BOATS WHERE BID=10;

no rows selected


Execution Plan
----------------------------------------------------------
Plan hash value: 2799518614

-------------------------------------------------------------------------------------
| Id  | Operation                   | Name  | Rows  | Bytes | Cost (%cpu)| Time     |
-------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT            |       |     1 |    16 |     1   (0)| 00:00:01 |
|   1 |  TABLE ACCESS BY INDEX ROWID| BOATS |     1 |    16 |     1   (0)| 00:00:01 |
|*  2 |   INDEX UNIQUE SCAN         | B_PK  |     1 |       |     0   (0)| 00:00:01 |
-------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   2 - access("BID"=10)

解决方法

在您的问题文本中,您似乎在描述sql_id和/或hash_value.这是sql语句文本的哈希值,也是Oracle用于确定共享池中是否已存在特定sql语句的哈希值.但是,您在示例中显示的是plan_hash_value,它是为sql语句生成的计划的哈希值.两者之间可能存在多对多的关系.单个sql语句(sql_id / hash_value)可以有多个不同的计划(plan_hash_value),并且多个不同的sql语句可以共享同一个计划.

因此,例如,如果我编写两个不同的sql语句来查询EMP表中的特定行,我将获得相同的plan_hash_value.

sql> set autotrace traceonly;
sql> select * from emp where ename = 'BOB';

no rows selected


Execution Plan
----------------------------------------------------------
Plan hash value: 3956160932

--------------------------------------------------------------------------
| Id  | Operation         | Name | Rows  | Bytes | Cost (%cpu)| Time     |
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      |     1 |    39 |     3   (0)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| EMP  |     1 |    39 |     3   (0)| 00:00:01 |
--------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter("ENAME"='BOB')


sql> ed
Wrote file afiedt.buf

  1* select * FROM emp WHERE ename = 'BOB'
sql> /

no rows selected


Execution Plan
----------------------------------------------------------
Plan hash value: 3956160932

--------------------------------------------------------------------------
| Id  | Operation         | Name | Rows  | Bytes | Cost (%cpu)| Time     |
--------------------------------------------------------------------------
|   0 | SELECT STATEMENT  |      |     1 |    39 |     3   (0)| 00:00:01 |
|*  1 |  TABLE ACCESS FULL| EMP  |     1 |    39 |     3   (0)| 00:00:01 |
--------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter("ENAME"='BOB')

但是,如果我查看v $sql,我会看到生成了两个不同的sql_id和hash_value值

sql> set autotrace off;
sql> ed
Wrote file afiedt.buf

  1  select sql_id,sql_text,hash_value,plan_hash_value
  2    from v$sql
  3   where sql_text like 'select%BOB%'
  4*    and length(sql_text) < 50
sql> /

sql_ID        sql_TEXT                                 HASH_VALUE PLAN_HASH_VALUE
------------- ---------------------------------------- ---------- ---------------
161v96c0v9c0n select * FROM emp WHERE ename = 'BOB'      28618772      3956160932
cvs1krtgzfr78 select * from emp where ename = 'BOB'    1610046696      3956160932

Oracle认识到这两个语句是具有不同sql_id和hash_value哈希值的不同查询.但它们都碰巧生成了相同的计划,因此最终得到了相同的plan_hash_value.

原文链接:https://www.f2er.com/mssql/74934.html

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