方法一：
代码如下:
SELECT TOP 页大小 *
FROM table1
WHERE id NOT IN
(
SELECT TOP 页大小*(页数-1) id FROM table1 ORDER BY id
)
ORDER BY id
FROM table1
WHERE id NOT IN
(
SELECT TOP 页大小*(页数-1) id FROM table1 ORDER BY id
)
ORDER BY id
方法二：
代码如下:
SELECT TOP 页大小 *
FROM table1
WHERE id >
(
SELECT ISNULL(MAX(id),0)
FROM
(
SELECT TOP 页大小*(页数-1) id FROM table1 ORDER BY id
) A
)
ORDER BY id
FROM table1
WHERE id >
(
SELECT ISNULL(MAX(id),0)
FROM
(
SELECT TOP 页大小*(页数-1) id FROM table1 ORDER BY id
) A
)
ORDER BY id
方法二倒序：
代码如下:
SELECT TOP 页大小 *
FROM table1
WHERE ID <=
(
SELECT ISNULL(MIN(ID),(SELECT MAX(ID) FROM table1 ))
FROM
(
SELECT TOP (页大小*(页数-1)) ID FROM tbl_files ORDER BY ID DESC
) A
)
ORDER BY ID DESC
FROM table1
WHERE ID <=
(
SELECT ISNULL(MIN(ID),(SELECT MAX(ID) FROM table1 ))
FROM
(
SELECT TOP (页大小*(页数-1)) ID FROM tbl_files ORDER BY ID DESC
) A
)
ORDER BY ID DESC
方法三
代码如下:
SELECT TOP 页大小 *
FROM
(
SELECT ROW_NUMBER() OVER (ORDER BY id) AS RowNumber,* FROM table1
) A
WHERE RowNumber > 页大小*(页数-1)
FROM
(
SELECT ROW_NUMBER() OVER (ORDER BY id) AS RowNumber,* FROM table1
) A
WHERE RowNumber > 页大小*(页数-1)
分页方案二：(利用ID大于多少和SELECT TOP分页）效率最高，需要拼接sql语句
分页方案一：(利用Not In和SELECT TOP分页) 效率次之，需要拼接sql语句
分页方案三：(利用sql的游标存储过程分页) 效率最差，但是最为通用PS:这三条方案是在网上搜到的，做分页的时候选用的方案二，发现直接套用语句不能满足要求，因为根据发帖顺序，是需要倒序排列的，就是最新发帖需要排到最前面，于是仿照方案二改成了倒序，希望对大家有所帮助。
