linux – 获取不在file2中的file1行

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我有两个很长但已排序的文件.如何获取不在第二个文件中的第一个文件的所有行? @H_301_2@文件1

0000_aaa_b
0001_bccc_b
0002_bcc <------ file2 have not that line
0003_aaa_d
0006_xxx
...
@H_301_2@文件2

0000_aaa_b
0001_bccc_b
0003_aaa_d
0006_xxx
...

解决方法

这是comm命令的用途:
$comm -3 file1 file2
0002_bcc
@H_301_2@来自man comm:

DESCRIPTION

   Compare sorted files FILE1 and FILE2 line by line.

   With  no  options,produce  three-column  output.  Column one contains
   lines unique to FILE1,column two contains lines unique to  FILE2,and
   column three contains lines common to both files.

   -1     suppress column 1 (lines unique to FILE1)

   -2     suppress column 2 (lines unique to FILE2)

   -3     suppress column 3 (lines that appear in both files)
原文链接:https://www.f2er.com/linux/397352.html

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