每个引用都需要存储在DB表行中.接收推荐的客户应该看到该活动的通知.
创建新的推荐并发送事件：
$totalRefers = [];
foreach ($array as $to) {
$refer = new ClientReferral;
$refer->user_id = $user_id;
$refer->by = $by;
$refer->to = $to;
$refer->save();
array_push($totalRefers,$refer);
ReferralSent::dispatch($refer); // Here is the Event
}
return response()->json([
'status' => 'Success','message' => 'Client referred successfully to selected professionals.','data' => $totalRefers
],200);
事件broadcastOn()方法：
public function broadcastOn() {
return new PrivateChannel('referral.' . $this->referral->id);
}
这个频道：
Broadcast::channel('referral.{id}',function ($user,$id) {
// let's say it's true for the time being
return true;
});
并且请求是一个Ajax POST,所以在成功回调中：
console.log('referral created');
res.data.forEach(function(entry) {
// window.custom.userId is the authenticated user ID:
if (entry.refer_to == window.custom.userId) {
window.Echo.private('referral.' + entry.id).listen('ReferralSent',({data}) => {
console.log('You have received a new referral');
});
}
});
现在当前代码的问题是接收器无法订阅此通道,因为事件是动态创建的,并且我不能将通道名称设置为静态,因为引用是在运行时进行的.
接收方如何订阅和收听动态事件？
有了这个逻辑,我想得到特定的推荐及其数据,以便在HTML的通知栏中显示它.
我怎样才能做到这一点？
