{
    "name": "somenameofevent","type": "event","data": {
        "object": {
            "age": "18","petName": "18"
        },"desct": {
        }
    }
}

我有2个像这样的对象

public class CustEvent
{
    [JsonProperty("name")]
    public string Name { get; set; }
    [JsonProperty("type")]
    public string EventType{ get; set; }
    [JsonProperty("data")]
    public SomeData Data{ get; set; }
}

public class SomeData
{
    [JsonProperty("object")]
    public String SomeObject { get; set;}
    [JsonProperty("dsct")]
    public String SomeDesct { get; set; }
}

我用来解析json对象Newtonsoft.NET库.以及如何将RAW JSON转换为SomeObject,SomeDesct属性？在JSON中,“data.object …”是复杂的对象,我想只获得RAW JSON String到这些属性.你可以帮我吗 ？