javascript实现数独解法

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生生把写过的java版改成javascript版,第一次写,很不专业,见谅。唉,我是有多闲。

代码如下:
> j & 1) == 1) { board = board.concat(String.fromCharCode(j + 49)); } } board = board.concat("]"); } return board; }, check: function () { var checkpoint = [0,12,24,28,40,52,56,68,80]; for (var i in checkpoint) { var r,b,c; r = b = c = this.cell[checkpoint[i]]; for (j = 0; j < 8; j++) { c ^= this.cell[this.getX(checkpoint[i])[j]]; b ^= this.cell[this.getX(checkpoint[i])[8 + j]]; r ^= this.cell[this.getX(checkpoint[i])[16 + j]]; } if ((r & b & c) != 0x1FF) { return false; } } return true; }, bitCount: function (i) { var n = 0; for (var j = 0; j < 9; j++) { if ((i >> j & 1) == 1) n++; } return n; }, numberOfTrailingZeros: function(i){ var n = 0; for (var j = 0; j < 9; j++) { if ((i >> j & 1) ==0) n++; else{ break; } } return n; }, updateCandidates: function () { for (var i in this.fixed) { var opt = 0x1FF ^ this.cell[this.fixed[i]]; for (var j = 0; j < 24; j++) { this.cell[this.getX(this.fixed[i])[j]] &= opt; //!notice if (this.cell[this.getX(this.fixed[i])[j]] == 0) { //console.log("Error-0 candidate:"+x[this.fixed[i]][j]); return false; } } } return true; }, seekUniqueCandidate: function () { for (var bidx in this.blank) { var row = 0,col = 0,Box = 0; for (i = 0; i < 8; i++) { row |= this.cell[this.getX(this.blank[bidx])[i]]; box |= this.cell[this.getX(this.blank[bidx])[8 + i]]; col |= this.cell[this.getX(this.blank[bidx])[16 + i]]; } if (this.bitCount(this.cell[this.blank[bidx]] & ~row) == 1) { this.cell[this.blank[bidx]] &= ~row; continue; } if (this.bitCount(this.cell[this.blank[bidx]] & ~col) == 1) { this.cell[this.blank[bidx]] &= ~col; continue; } if (this.bitCount(this.cell[this.blank[bidx]] & ~box) == 1) { this.cell[this.blank[bidx]] &= ~box; } } }, seekFilledable: function () { this.fixed = []; var _del=[]; for (var i in this.blank) { if (this.bitCount(this.cell[this.blank[i]]) == 1) { this.fixed.push(this.blank[i]); //console.log("fixed:"+this.blank[i]+"=>"+this.cell[this.blank[i]]); //this.blank.splice(i,1);//to delete it in the loop would cause bug _del.push(i); } } while(_del.length>0){ this.blank.splice(_del.pop(),1); } }, seekMutexCell: function () { var two = []; for (var n in this.blank) { if (this.bitCount(this.cell[this.blank[n]]) == 2) { two.push(this.blank[n]); } } for (var i = 0; i < two.length; i++) { for (var j = i + 1; j < two.length; j++) { if (this.cell[two[i]] == this.cell[two[j]]) { var opt = ~this.cell[two[i]]; if (parseInt(two[i] / 9) ==parseInt(two[j] / 9)) { for (n = 0; n < 8; n++) { this.cell[this.getX(two[i])[n]] &= opt; } } if ((two[i] - two[j]) % 9 == 0) { for (n = 8; n < 16; n++) { this.cell[this.getX(two[i])[n]] &= opt; } } if ((parseInt(two[i] / 27) * 3 + parseInt(two[i] % 9 / 3)) == (parseInt(two[j] / 27) * 3 + parseInt(two[j] % 9 / 3))) { for (n = 16; n < 24; n++) { this.cell[this.getX(two[i])[n]] &= opt; } } this.cell[two[j]] = ~opt; } } } }, basicSolve: function () { do { if (!this.updateCandidates(this.fixed)) { this.backForward(); } this.seekUniqueCandidate(); this.seekMutexCell(); this.seekFilledable(); } while (this.fixed.length != 0); return this.blank.length == 0; }, setTrialCell: function() { for (var i in this.blank) { if (this.bitCount(this.cell[this.blank[i]]) == 2) { var trialValue = 1 << this.numberOfTrailingZeros(this.cell[this.blank[i]]); var waitingValue = this.cell[this.blank[i]] ^ trialValue; //console.log("try:[" + this.blank[i] + "]->" + (this.numberOfTrailingZeros(trialValue) + 1) + "#" + (this.numberOfTrailingZeros(waitingValue) + 1)); this.cell[this.blank[i]] = trialValue; this.trials.push(this.createTrialPoint(this.blank[i],waitingValue,this.cell)); return true; } } return false; }, backForward: function() { if (this.trials.length==0) { console.log("Maybe no solution!"); return; } var back = this.trials.pop(); this.reset(back.data); this.cell[back.idx] = back.val; this.fixed.push(back.idx); //console.log("back:[" + back.idx + "]->" + (this.numberOfTrailingZeros(back.val) + 1)); }, reset: function(data) { this.blank=[]; this.fixed=[]; this.cell=data.concat(); for (var i = 0; i < 81; i++) { if (this.bitCount(this.cell[i]) != 1) { this.blank.push(i); } else { this.fixed.push(i); } } }, trialSolve: function() { while (this.blank.length!=0) { if (this.setTrialCell()) { this.basicSolve(); } else { if (this.trials.length==0) { //console.log("Can't go backforward! Maybe no solution!"); break; } else { this.backForward(); this.basicSolve(); } } } }, play: function() { console.log(this.showBoard()); var start = new Date().getMilliseconds(); if (!this.basicSolve()) { this.trialSolve(); } var end = new Date().getMilliseconds(); console.log(this.showBoard()); if (this.check()) { console.log("[" + (end - start) + "ms OK!]"); } else { console.log("[" + (end - start) + "ms,cannot solve it?"); } //return this.showBoard(); }, getX:function(idx){ var neighbors=new Array(24); var Box=new Array(0,1,2,9,10,11,18,19,20); var r=parseInt(idx/9); var c=idx%9; var xs=parseInt(idx/27)*27+parseInt(idx%9/3)*3; var i=0; for(var n=0;n<9;n++){ if(n==c)continue; neighbors[i++]=r*9+n; } for(var n=0;n<9;n++){ if(n==r)continue; neighbors[i++]=c+n*9; } for(var n=0;n<9;n++){ var t=xs+Box[n]; if(t==idx)continue; neighbors[i++]=t; } return neighbors; }, createTrialPoint:function(idx,val,board) { var tp = {}; tp.idx = idx; tp.val = val; tp.data = board.concat(); return tp; } }; //Sudoku.init("000000500000008300600100000080093000000000020700000000058000000000200017090000060"); //Sudoku.init("530070000600195000098000060800060003400803001700020006060000280000419005000080079"); Sudoku.init("800000000003600000070090200050007000000045700000100030001000068008500010090000400"); Sudoku.play();

以上就是关于使用javascript实现数独解法的全部代码了,希望大家能够喜欢。

原文链接:https://www.f2er.com/js/55290.html

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