JavaScript实现信用卡校验方法

前端之家收集整理的这篇文章主要介绍了JavaScript实现信用卡校验方法前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。

@H_404_0@本文实例讲述了JavaScript实现信用卡校验方法分享给大家供大家参考。具体分析如下:


@H_404_0@这里JavaScript版的信用卡校验代码,采用了Luhn算法


<div class="jb51code">
<pre class="brush:js;">
function isValidCreditCard(type,ccnum) {
if (type == "Visa") {
// Visa: length 16,prefix 4,dashes optional.
var re = /^4\d{3}-?\d{4}-?\d{4}-?\d{4}$/;
} else if (type == "MC") {
// Mastercard: length 16,prefix 51-55,dashes optional.
var re = /^5[1-5]\d{2}-?\d{4}-?\d{4}-?\d{4}$/;
} else if (type == "Disc") {
// Discover: length 16,prefix 6011,dashes optional.
var re = /^6011-?\d{4}-?\d{4}-?\d{4}$/;
} else if (type == "AmEx") {
// American Express: length 15,prefix 34 or 37.
var re = /^3[4,7]\d{13}$/;
} else if (type == "Diners") {
// Diners: length 14,prefix 30,36,or 38.
var re = /^3[0,6,8]\d{12}$/;
}
if (!re.test(ccnum)) return false;
// Remove all dashes for the checksum
//checks to eliminate negative numbers
ccnum = ccnum.split("-").join("");
// Checksum ("Mod 10")
// Add even digits in even length strings
//or odd digits in odd length strings.
var checksum = 0;
for (var i=(2-(ccnum.length % 2)); i<=ccnum.length; i+=2) {
checksum += parseInt(ccnum.charAt(i-1));
}
// Analyze odd digits in even length strings
//or even digits in odd length strings.
for (var i=(ccnum.length % 2) + 1; i<ccnum.length; i+=2) {
var digit = parseInt(ccnum.charAt(i-1)) * 2;
if (digit < 10) { checksum += digit; }
else { checksum += (digit-9); }
}
if ((checksum % 10) == 0) return true; else return false;
}

@H_404_0@希望本文所述对大家的javascript程序设计有所帮助。

原文链接:https://www.f2er.com/js/54890.html

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