我编写了一个非常慢的函数来生成从AA000到ZZ999的代码(按顺序而非随机).我已经得出结论,必须有一个更好的方法来做到这一点.有关如何加快速度的任何建议吗？
function generateAlphaNumeric(){
theAlphabet = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'];
resultArrray = [];
resultArrray2 = [];
teller = 0;
for(i in theAlphabet){
for(x in theAlphabet){
resultArrray[teller] = theAlphabet[i] + theAlphabet[x];
teller++;
}
}
teller = 0;
for(x = 0; x<10; x++){
for(y = 0; y<10; y++){
for(z = 0; z<10; z++){
resultArrray2[teller] = x.toString() + y.toString() +z.toString();
teller++;
}
}
}
teller = 0;
finalArray = [];
for(index in resultArrray){
for(i in resultArrray2){
finalArray[teller] = resultArrray[index] + resultArrray2[i];
teller++;
}
}
//console.log(resultArrray);
//console.log(resultArrray2);
console.log(finalArray);
}
最佳答案
这应该快得多：
原文链接：https://www.f2er.com/js/428963.htmlvar theAlphabet = ['A','Z'];
var theDigits = ['0','1','2','3','4','5','6','7','8','9'];
var result = [];
for (var i=0 ; i<26 ; i++) {
var prefix1 = theAlphabet[i];
for (var j=0 ; j<26; j++) {
var prefix2 = prefix1 + theAlphabet[j];
for(var x = 0; x<10; x++){
var prefix3 = prefix2 + theDigits[x];
for(var y = 0; y<10; y++){
var prefix4 = prefix3 + theDigits[y];
for(var z = 0; z<10; z++){
result.push(prefix4 + theDigits[z]);
}
}
}
}
}
主要观点：
但是,我不知道这样详尽的清单是如何有用的.正好有26 * 26 * 1000个不同的代码.因此,不是使用所有代码维护数组,而是简单地构建一个生成所请求的特定代码的函数是有意义的：
function getCode(number) {
var z = number % 10;
number -= z; number /= 10;
var y = number % 10;
number -= y; number /= 10;
var x = number % 10;
number -= x; number /= 10;
var a = number % 26;
number -= a; number /= 26;
var b = number;
return theAlphabet[a] + theAlphabet[b] + theDigits[x] + theDigits[y] + theDigits[z];
}
