我需要以深度优先的方式遍历树结构的帮助.我无法想出一个算法来正确地做到这一点.
@H_502_11@解决方法
我的意见是这样的：
[
["A","B","C"],["1","2"],["a","b","c","d"]
]
输出应采取以下形式：
[
"A/1/a","A/1/b","A/1/c","A/1/d","A/2/a","A/2/b","A/2/c","A/2/d","B/1/a","B/1/b","B/1/c","B/1/d","B/2/a","B/2/b","B/2/c","B/2/d","C/1/a","C/1/b","C/1/c","C/1/d","C/2/a","C/2/b","C/2/c","C/2/d"
]
这应该做的工作：
function traverse(arr) {
var first = arr[0];
var ret = [];
if (arr.length == 1) {
for (var i = 0; i < first.length; i++) {
ret.push(first[i]);
}
} else {
for (var i = 0; i < first.length; i++) {
var inn = traverse(arr.slice(1));
for (var j = 0; j < inn.length; j++) {
ret.push(first[i] + '/' + inn[j]);
}
}
}
return ret;
}
var inp = [
["A","d"]
];
var out = traverse(inp);
console.log(out);
