javascript – 如何检测照片/视频是从相机拍摄还是从iphone Safari中的相机胶卷导入

在我的网站上,我有一个文件输入标签来上传照片/视频.
当在移动safari中打开网站时,当我们点击文件输入时,会打开一个操作表,其中有3个选项拍摄照片或视频,选择现有并取消.
无论如何在js中确定文件是从相机拍摄的(拍摄照片或视频),还是从相机胶卷导入(选择现有的)？

解决方法

我有一个从这个实现的 PHP 解决方案,我不确定这会对你有所帮助,但这里是代码：

<?PHP

$camera = cameraUsed("C:\Users\Ale\Pictures\sep7imodia.jpg");
echo "Camera Used: " . $camera['make'] . " " . $camera['model'] . "<br />";
echo "Exposure Time: " . $camera['exposure'] . "<br />";
echo "Aperture: " . $camera['aperture'] . "<br />";
echo "ISO: " . $camera['iso'] . "<br />";
echo "Date Taken: " . $camera['date'];

// This function is used to determine the camera details for a specific image. It returns an array with the parameters.

function cameraUsed($imagePath) {

// Check if the variable is set and if the file itself exists before continuing
if ((isset($imagePath)) and (file_exists($imagePath))) {

  // There are 2 arrays which contains the information we are after,so it's easier to state them both
  $exif_ifd0 = read_exif_data($imagePath,'IFD0',0);      
  $exif_exif = read_exif_data($imagePath,'EXIF',0);

  //error control
  $notFound = "Unavailable";

  // Make
  if (@array_key_exists('Make',$exif_ifd0)) {
    $camMake = $exif_ifd0['Make'];
  } else { $camMake = $notFound; }

  // Model
  if (@array_key_exists('Model',$exif_ifd0)) {
    $camModel = $exif_ifd0['Model'];
  } else { $camModel = $notFound; }

  // Exposure
  if (@array_key_exists('ExposureTime',$exif_ifd0)) {
    $camExposure = $exif_ifd0['ExposureTime'];
  } else { $camExposure = $notFound; }

  // Aperture
  if (@array_key_exists('ApertureFNumber',$exif_ifd0['COMPUTED'])) {
    $camAperture = $exif_ifd0['COMPUTED']['ApertureFNumber'];
  } else { $camAperture = $notFound; }

  // Date
  if (@array_key_exists('DateTime',$exif_ifd0)) {
    $camDate = $exif_ifd0['DateTime'];
  } else { $camDate = $notFound; }

  // ISO
  if (@array_key_exists('ISOSpeedRatings',$exif_exif)) {
    $camIso = $exif_exif['ISOSpeedRatings'];
  } else { $camIso = $notFound; }

  $return = array();
  $return['make'] = $camMake;
  $return['model'] = $camModel;
  $return['exposure'] = $camExposure;
  $return['aperture'] = $camAperture;
  $return['date'] = $camDate;
  $return['iso'] = $camIso;
  return $return;

} else {
  return false;
}
}

?>

您可以将$camera [‘date’]值与实际日期时间进行比较,如果有几秒钟的差异,您可以假设它刚刚被手机拍摄.

原文链接：https://www.f2er.com/js/157292.html

javascript – 如何检测照片/视频是从相机拍摄还是从iphone Safari中的相机胶卷导入

解决方法

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