我正在寻找一种方法来以下列方式集成Node.js Socket.io Apache：
我希望apache继续提供 HTML / JS文件.
我希望node.js监听端口8080上的连接.这样的事情：
我希望apache继续提供 HTML / JS文件.
我希望node.js监听端口8080上的连接.这样的事情：
var util = require("util"),app = require('http').createServer(handler),io = require('/socket.io').listen(app),fs = require('fs'),os = require('os'),url = require('url');
app.listen(8080);
function handler (req,res) {
fs.readFile(__dirname + '/index.html',function (err,data) {
if (err) {
res.writeHead(500);
return res.end('Error loading index.html');
}
res.writeHead(200);
res.end(data);
});
}
io.sockets.on('connection',function (socket) {
socket.emit('news',{ hello: 'world' });
socket.on('my other event',function (data) {
socket.emit('ok 1',{ hello: 'world' });
});
socket.on('clientMSG',function (data) {
socket.emit('ok 2',{ hello: 'world' });
});
});
如果我访问连接到此服务器的HTML,它可以工作,但我需要访问mydomian.com:8080/index.html.
我想要的是能够访问mydomian.com/index.html.并能够打开套接字连接：
<script>
var socket = io.connect('http://mydomain.com',{port: 8080});
socket.on('news',function (data) {
console.log(data);
socket.emit('my other event',{ my: 'data from the client' });
});
socket.on('connect',function (data) {
console.log("connect");
});
socket.on('disconnect',function (data) {
console.log("disconnect");
});
//call this function when a button is clicked
function sendMSG()
{
console.log("sendMSG");
socket.emit('clientMSG',{ msg: 'non-scheduled message from client' });
}
</script>
在这个例子中,当我转到URL中的端口8080时,我不得不使用fs.readFile.
有什么建议？韩国社交协会.
解决方法
从Apache端口80提供静态内容,并通过端口8080上的Socket.IO服务器提供动态/数据内容.您的Socket.IO应用程序中不需要app = require(‘http’).createServer(handler)
Apache端口80 | ————- |客户| ———— | Socket.IO端口8080
var io = require('socket.io').listen(8080);
io.sockets.on('connection',function (socket) {
io.sockets.emit('this',{ will: 'be received by everyone'});
socket.on('clientMSG',function (from,msg) {
console.log('I received a private message by ',from,' saying ',msg);
});
socket.on('disconnect',function () {
sockets.emit('user disconnected');
});
});
