Box ID="txtLineNumber" runat="server">Box>
Box ID="txtQty" runat="server"> Box>
Box ID="txtItemCode" runat="server"> Box>
301_7@
当用户单击添加按钮时,我想创建另一个带有行项ID的div并将其放在下一行.我创建了一个js文件,但我不知道该怎么做?
这是我到目前为止:
var itemCount = 0;
function getLineItem(number) {
var div = document.createElement('div');
$(div).attr("id","lineitem" + number);
var t1 = getTextBox("txt" + number.toString() + "1");
var t2 = getTextBox("txt" + number.toString() + "2");
var t3 = getTextBox("txt" + number.toString() + "3");
$(div).append(t1);
$(div).append(t2);
$(div).append(t3);
return $(div);
}
function getTextBox(id) {
var textBox = document.createElement('input');
$(textBox).attr("id",id);
return $(textBox);
}
var lineItemCount = 0;
$('#imgBtnAddNewLineItem').click(function() {
lineItemCount++;
$('#line-item').clone().attr('id',getLineItem(lineItemCount)).appendTo('#container');
});
});
@H_301_7@
最佳答案
$(document).ready(function() {
$('#imgBtnAddNewLineItem').click(function() {
$('#container').append('301_7@
更新2
像这样创建一个普通的按钮:
301_7@
更新**这也更新了评论等.. **
//Count the lineItems to make sure they are unique
var lineItemCount = 0;
//On document ready
$(document).ready(function() {
//On button click
$('#imgBtnAddNewLineItem').click(function(e) {
/*
ADD THE FOLLOWING LINE TO PREVENT THE POSTBACK
P.S. - Make sure you pass -e- to this function...
*/
e.preventDefault();
//Increase the lineitemcount
lineItemCount++;
//Add a new lineitem to the container,pass the lineItemCount to make sure getLineItem() can generate a unique lineItem with unique TextBox ids
$(container).append(getLineItem(lineItemCount));
});
});
//Create a new DIV with TextBoxes
function getLineItem(number) {
var div = document.createElement('div');
//Give the div a unique id
div.setAttribute('id','lineitem_' + number);
//pass unique values to the getTextBox() function
var t1 = getTextBox('txt_' + number + '_1');
var t2 = getTextBox('txt_' + number + '_2');
var t3 = getTextBox('txt_' + number + '_3');
div.appendChild(t1);
div.appendChild(t2);
div.appendChild(t3);
return div;
}
//Create a textBox,make sure the id passed to this function is unique...
function getTextBox(id) {
var textBox = document.createElement('input');
textBox.setAttribute('id',id);
textBox.setAttribute('name',id);
return textBox;
}
@H_301_7@
原文链接:https://www.f2er.com/jquery/428833.html