function tableToJSON(tableID) {
    return $(tableID + "  tr").map(function (row) {
        return row.descendants().pluck("innerHTML");
    }).toJSON();
}

解决方法

function tableToJson(table) {
    var data = [];

    // first row needs to be headers
    var headers = [];
    for (var i=0; i<table.rows[0].cells.length; i++) {
        headers[i] = table.rows[0].cells[i].innerHTML.toLowerCase().replace(/ /gi,'');
    }

    // go through cells
    for (var i=1; i<table.rows.length; i++) {

        var tableRow = table.rows[i];
        var rowData = {};

        for (var j=0; j<tableRow.cells.length; j++) {

            rowData[ headers[j] ] = tableRow.cells[j].innerHTML;

        }

        data.push(rowData);
    }       

    return data;
}

取自John Dyer’s Blog