使用Wicket AbstractAjaxBehavior与jQuery.ajax()

我已经使用jQuery AJax调用来发送 JSON,如 StackOverflow中所述

问题是我没有收到服务器上的任何数据.我可以看到调用确实达到了目标ajax行为 – 但在onRequest()方法中,RequestCycle dd不包含任何参数

我的Wicket代码：

AbstractAjaxBehavior ajaxSaveBehavIoUr = new AbstractAjaxBehavior(){
        private static final long serialVersionUID = 1L;

        @SuppressWarnings("unchecked")
        public void onRequest()
        {
            //get parameters
            final RequestCycle requestCycle = RequestCycle.get();



            final PageParameters pageParameters = new PageParameters(requestCycle.getRequest().getParameterMap());
            logger.info(" I have received something 1");

            for(String pkey: requestCycle.getRequest().getParameterMap().keySet()){
                String[] valArry= requestCycle.getRequest().getParameterMap().get(pkey);
                StringBuffer sb = new StringBuffer();
                for(String s: valArry) sb.append(s).append(",");
                logger.info("pk :"+ pkey + " = "+ sb.toString());
            }

            //do something using nice json library to produce a string of json

            logger.info(" I have received something 2");
            for(String key: pageParameters.keySet()){
                Object o= pageParameters.get(key);
                logger.info("received key : "+ key + "   = " +o.toString());                    
            }





            String data="ok";        

            requestCycle.setRequestTarget(new StringRequestTarget("application/json","utf-8",data));
        }


    };
    add(ajaxSaveBehavIoUr);
    String callBackURL= ajaxSaveBehavIoUr.getCallbackUrl().toString();

我的Javascript调用此方法

console.log(" call back url :"+ callBackURL);
           $.ajax({
                url: callBackURL,type: 'post',cache: false,data:JSON.stringify(ccbArry[0]),contentType: 'application/json',dataType: 'json',complete: function() {
                        alert(" completed okey dokey!")
                }

            });

从我的Firebug控制台,我可以看到JSON POST成功完成并且警报(“完成的okey dokey！”)dos被触发.

问题是在Wicket上,AbstractAjaxBehavior无法在RequestCycle中找到任何参数.

有什么我想念的吗？有趣的是,我运行这是调试器,因为我找不到任何参数.这看起来像编码问题.

从Firebug,我可以看到这是发出的电话

http://localhost:8080/mywebapp-web-1.0-SNAPSHOT/?wicket:interface=:0::IActivePageBehaviorListener:0:&wicket:ignoreIfNotActive=true&%7B%22type%22%3A9504%2C%22sourceNewsClipBean%22%3A%7B%22type%22%3A9503%2C%22id%22%3A%224cf05752acc1d6aebface86d%22%2C%22typeString%22%3A%22NEWSCLIP_TYPE%22%7D%2C%22startOffset%22%3A%22195%22%2C%22clipDuration%22%3A%22297%22%7D=

不知何故,这些参数在RequestCycle中没有出现.它看起来像一个狡猾的问题.有任何想法吗？

@H_502_25@解决方法

好吧,我找到了解决方案：关键是不使用requestCycle.getRequest().getParameterMap()从浏览器中读取JSON.而是直接从servlet输入流中读取数据,如下所示：
有用 .

public void onRequest()
        {
            //get parameters
            final RequestCycle requestCycle = RequestCycle.get();


            WebRequest wr=(WebRequest)requestCycle.getRequest();

            HttpServletRequest hsr= wr.getHttpServletRequest() ;

            try {
                BufferedReader br = hsr.getReader();

                       String  jsonString = br.readLine();
                       if((jsonString==null) || jsonString.isEmpty()){
                           logger.error(" no json found");
                       }
                       else {
                           logger.info(" json  is :"+ jsonString);
                       }



            } catch (IOException ex) {
                logger.error(ex);
            }


            // json string to retir to the jQuery onSuccess function
            String data=getReturnJSONValue();

            logger.info("returning json :"+ data);
            IRequestTarget t = new StringRequestTarget("application/json","UTF-8",data);
            getRequestCycle().setRequestTarget(t);


            //requestCycle.setRequestTarget(new StringRequestTarget("application/json",data));
        }

原文链接：https://www.f2er.com/jquery/177368.html

使用Wicket AbstractAjaxBehavior与jQuery.ajax()

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