我有如下实体

类ProgressNote

@Entity
public class ProgressNote implements Serializable{

    @Id
    private NotesKey notesKey = new NotesKey();

    private Set@H_404_10@
类NotesKey

@Embeddable
public class NotesKey implements Serializable{

    private Byte noteNumber;

    @Temporal(javax.persistence.TemporalType.DATE)
    @Column(name="ddate")
    private Date noteDate;

    private Patient patient;

    public Byte getNoteNumber() {
        return noteNumber;
    }

    public void setNoteNumber(Byte noteNumber) {
        this.noteNumber = noteNumber;
    }

    public Date getNoteDate() {
        return noteDate;
    }

    public void setNoteDate(Date noteDate) {
        this.noteDate = noteDate;
    }

    @ManyToOne(fetch=FetchType.LAZY)
    @Access(AccessType.PROPERTY)
    public Patient getPatient() {
        return patient;
    }

    public void setPatient(Patient patient) {
        this.patient = patient;
    }

    @Override
    public int hashCode() {
        ........
    }

    @Override
    public boolean equals(Object obj) {
        ........
    }

}
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类PatientObjective

@Entity
public class PatientObjective implements Serializable{

    @Id
    private PatientObjectiveKey patientObjectiveKey;


    public PatientObjectiveKey getPatientObjectiveKey() {
        return patientObjectiveKey;
    }
    public void setPatientObjectiveKey(PatientObjectiveKey patientObjectiveKey) {
        this.patientObjectiveKey = patientObjectiveKey;
    }

}
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类PatientObjectiveKey

@Embeddable
public class PatientObjectiveKey implements Serializable{

    private Objective objective;

    private Byte noteNumber;

    @Temporal(javax.persistence.TemporalType.DATE)
    @Column(name="ddate")
    private Date noteDate;

    private Patient patient;

    @ManyToOne(fetch=FetchType.LAZY)
    @Access(AccessType.PROPERTY)
    public Objective getObjective() {
        return objective;
    }

    public void setObjective(Objective objective) {
        this.objective = objective;
    }

    public Byte getNoteNumber() {
        return noteNumber;
    }

    public void setNoteNumber(Byte noteNumber) {
        this.noteNumber = noteNumber;
    }

    public Date getNoteDate() {
        return noteDate;
    }

    public void setNoteDate(Date noteDate) {
        this.noteDate = noteDate;
    }

    @ManyToOne(fetch=FetchType.LAZY)
    @Access(AccessType.PROPERTY)
    public Patient getPatient() {
        return patient;
    }

    public void setPatient(Patient patient) {
        this.patient = patient;
    }

    @Override
    public int hashCode() {
        .......
    }

    @Override
    public boolean equals(Object obj) {
        ........
    }

}
@H_404_10@
我使用这个命名查询后


@NamedQuery(name = “findAllProgressNoteWithObjective”,query = “from

  ProgressNote p inner join fetch p.patientObjectives as o where

  p.notesKey.patient.id = :patientId)”) using spring hibernate template findByNamedQueryAndNamedParam

在表I中有2个ProgressNotes,其中一个具有单个目标,另一个具有17个目标.我在Java中得到如下结果.
查询生成为

select progressno0_.ddate as ddate46_0_,progressno0_.noteNumber as noteNumber46_0_,progressno0_.patient_id as patient17_46_0_,patientobj1_.ddate as ddate36_1_,patientobj1_.noteNumber as noteNumber36_1_,patientobj1_.objective_id as objective5_36_1_,patientobj1_.patient_id as patient6_36_1_,progressno0_.assessment as assessment46_0_,progressno0_.bloodPressure1 as bloodPre4_46_0_,progressno0_.bloodPressure2 as bloodPre5_46_0_,progressno0_.creationDate as creation6_46_0_,progressno0_.height as height46_0_,progressno0_.lastUpdatedDate as lastUpda8_46_0_,progressno0_.plans as plans46_0_,progressno0_.status as status46_0_,progressno0_.subject as subject46_0_,progressno0_.temprature as temprature46_0_,progressno0_.tempratureUnit as temprat13_46_0_,progressno0_.lastid as lastid46_0_,progressno0_.waist as waist46_0_,progressno0_.weight as weight46_0_,progressno0_.weightUnit as weightUnit46_0_,patientobj1_.remark as remark36_1_,patientobj1_.value as value36_1_,patientobj1_.ddate as ddate46_0__,patientobj1_.noteNumber as noteNumber46_0__,patientobj1_.patient_id as patient6_46_0__,patientobj1_.ddate as ddate0__,patientobj1_.noteNumber as noteNumber0__,patientobj1_.objective_id as objective5_0__,patientobj1_.patient_id as patient6_0__ from pnheader progressno0_ inner join pnobjremark patientobj1_ on progressno0_.ddate=patientobj1_.ddate and progressno0_.noteNumber=patientobj1_.noteNumber and progressno0_.patient_id=patientobj1_.patient_id where progressno0_.patient_id=? 
@H_404_10@
题
问题我看到为什么我得到ProgressNote的多个单个实例(id = 152).有没有办法可以避免这种重复？
如果有人解释或指出我正确的方向,我将非常感激.
使用Hibernate 3.6,MysqL 5.6.10