if (lineStyle == 5 || lineStyle == 21 || lineStyle == 82 || lineStyle == 83 || lineStyle == 3) {
lineStyleString = "DOUBLE";
} else if (lineStyle == 6 || lineStyle == 35 || lineStyle == 39 || lineStyle == 30) {
lineStyleString = "DOTTED" ;
} else if (lineStyle == 26 || lineStyle == 27 || lineStyle == 28 || lineStyle == 29 || lineStyle == 1) {
lineStyleString = "SOLID";
} else if(lineStyle == -1) {
lineStyleString = "NONE";
}
我们如何在Java中以智能方式处理此代码？切换案例,枚举或密钥对值模式？
最佳答案
您的条件看起来更随机.
原文链接：https://www.f2er.com/java/437394.htmlSwitch在这里看起来不错
switch(lineStyle) {
case 5:
case 21:
case 82:
case 83:
case 3:
lineStyleString = "DOUBLE";
break;
.. // add more cases
}
或者我更喜欢创建实用方法
public static boolean contains(int expecxted,int... vals) {
for (int i = 0; i < vals.length; i++) {
if (expecxted == vals[i]) {
return true;
}
}
return false;
}
你可以像使用它一样
if (contains(lineStyle,5,21,82,83,3)) {
lineStyleString = "DOUBLE";
} else if(contains(lineStyle,6,35,39,30)){
lineStyleString = "DOTTED";
}
