java – 在ComboBox中为FilteredList设置谓词会影响输入

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我已经实现了一个ComboBox,其列表由ComboBox TextField中的输入过滤.它可以正常工作,因为你可能期望这种控件的过滤器工作.列表中显示列表中以输入文本开头的每个项目.

我只有一个小问题.如果我从列表中选择一个项目,然后尝试删除文本字段中的最后一个字符,则没有任何反应.如果我从列表中选择一个项目,然后尝试删除除最后一个之外的任何其他字符,则会删除整个字符串.只有这是我在ComboBox中做的第一件事时才会出现这两个问题.如果我先在组合框中写一些东西,或者我第二次选择一个项目,则不会出现所描述的任何问题.

对我来说真正奇怪的是,这些问题似乎是由谓词设置引起的(如果我注释掉setPredicate的调用,一切正常).这很奇怪,因为我认为这应该只影响为谓词设置的列表.它不应该影响ComboBox的其余部分.

import javafx.application.Application;
import javafx.beans.value.ChangeListener;
import javafx.beans.value.ObservableValue;
import javafx.collections.FXCollections;
import javafx.collections.ObservableList;
import javafx.collections.transformation.FilteredList;
import javafx.scene.Scene;
import javafx.scene.control.ComboBox;
import javafx.scene.layout.VBox;
import javafx.stage.Stage;
import javafx.util.StringConverter;

public class TestInputFilter extends Application {
    public void start(Stage stage) {
        VBox root = new VBox();

        ComboBoxBoxItem> cb = new ComboBoxBoxItem>();
        cb.setEditable(true);

        cb.setConverter(new StringConverterBoxItem>() {

            @Override
            // To convert the ComboBoxItem to a String we just call its
            // toString() method.
            public String toString(ComboBoxItem object) {
                return object == null ? null : object.toString();
            }

            @Override
            // To convert the String to a ComboBoxItem we loop through all of
            // the items in the comboBox dropdown and select anyone that starts
            // with the String. If we don't find a match we create our own
            // ComboBoxItem.
            public ComboBoxItem fromString(String string) {
                return cb.getItems().stream().filter(item -> item.getText().startsWith(string)).findFirst()
                        .orElse(new ComboBoxItem(string));
            }
        });

        ObservableListBoxItem> options = FXCollections.observableArrayList(new ComboBoxItem("One is a number"),new ComboBoxItem("Two is a number"),new ComboBoxItem("Three is a number"),new ComboBoxItem("Four is a number"),new ComboBoxItem("Five is a number"),new ComboBoxItem("Six is a number"),new ComboBoxItem("Seven is a number"));
        FilteredListBoxItem> filteredOptions = new FilteredListBoxItem>(options,p -> true);
        cb.setItems(filteredOptions);

        InputFilter inputFilter = new InputFilter(cb,filteredOptions);
        cb.getEditor().textProperty().addListener(inputFilter);

        root.getChildren().add(cb);

        stage.setScene(new Scene(root));
        stage.show();
    }

    public static void main(String[] args) {
        launch();
    }

    class ComboBoxItem {

        private String text;

        public ComboBoxItem(String text) {
            this.text = text;
        }

        public String getText() {
            return text;
        }

        @Override
        public String toString() {
            return text;
        }
    }

    class InputFilter implements ChangeListenerBoxBoxItem> Box;
        private FilteredListBoxItem> items;

        public InputFilter(ComboBoxBoxItem> Box,FilteredListBoxItem> items) {
            this.Box = Box;
            this.items = items;
        }

        @Override
        public void changed(ObservableValueBox.getSelectionModel().getSelectedItem() != null
                    ? Box.getSelectionModel().getSelectedItem().getText() : null;

            // If an item is selected and the value of in the editor is the same
            // as the selected item we don't filter the list.
            if (selected != null && value.equals(selected)) {
                items.setPredicate(item -> {
                    return true;
                });
            } else {
                items.setPredicate(item -> {
                    if (item.getText().toUpperCase().startsWith(value.toUpperCase())) {
                        return true;
                    } else {
                        return false;
                    }
                });
            }
        }
    }
}

编辑:我试图在绝望的尝试中覆盖关键监听器来解决问题:

cb.getEditor().addEventFilter(KeyEvent.KEY_PRESSED,e -> {
    TextField editor = cb.getEditor();
    int caretPos = cb.getEditor().getCaretPosition();
    StringBuilder text = new StringBuilder(cb.getEditor().getText());

    // If BACKSPACE is pressed we remove the character at the index
    // before the caret position.
    if (e.getCode().equals(KeyCode.BACK_SPACE)) {
        // BACKSPACE should only remove a character if the caret
        // position isn't zero.
        if (caretPos > 0) {
            text.deleteCharAt(--caretPos);
        }
        e.consume();
    }
    // If DELETE is pressed we remove the character at the caret
    // position.
    else if (e.getCode().equals(KeyCode.DELETE)) {
        // DELETE should only remove a character if the caret isn't
        // positioned after that last character in the text.
        if (caretPos < text.length()) {
            text.deleteCharAt(caretPos);
        }
    }
    // If LEFT key is pressed we move the caret one step to the left.
    else if (e.getCode().equals(KeyCode.LEFT)) {
        caretPos--;
    }
    // If RIGHT key is pressed we move the caret one step to the right.
    else if (e.getCode().equals(KeyCode.RIGHT)) {
        caretPos++;
    }
    // Otherwise we just add the key text to the text.
    // TODO We are currently not handling UP/DOWN keys (should move
    // caret to the end/beginning of the text).
    // TODO We are currently not handling keys that doesn't represent
    // any symbol,like ALT. Since they don't have a text,they will
    // just move the caret one step to the right. In this case,that
    // caret should just hold its current position.
    else {
        text.insert(caretPos++,e.getText());
        e.consume();
    }

    final int finalPos = caretPos;

    // We set the editor text to the new text and finally we move the
    // caret to its new position.
    editor.setText(text.toString());
    Platform.runLater(() -> editor.positionCaret(finalPos));
});

// We just consume KEY_RELEASED and KEY_TYPED since we don't want to
// have duplicated input.
cb.getEditor().addEventFilter(KeyEvent.KEY_RELEASED,e -> {
    e.consume();
});
cb.getEditor().addEventFilter(KeyEvent.KEY_TYPED,e -> {
    e.consume();
});

可悲的是,这也没有解决问题.如果我选择“Three is a number”项,然后尝试删除“Three”中的最后一个“e”,这是text属性将在之间切换的值:

TextProperty: Three is a number
TextPropery: Thre is a number
TextPropery: 

所以它首先删除了正确的字符,但是由于某种原因它删除了整个字符串.如前所述,这只是因为谓词已经设置,而且只有在我第一次选择项目后进行第一次输入时才会发生这种情况.

最佳答案
了Jonatan,

正如Manuel所说,一个问题是setPredicate()会在你更改组合框模型时触发你的changed()方法两次,但真正的问题是组合框会用适合的任何值覆盖编辑器值.以下是您症状的解释:

If I select an item from the list,and then try to remove the last
character in the textfield,nothing happens.

在这种情况下,最后一个char的删除实际上正在发生,但是第一次调用setPredicate()会匹配一个可能的项目(与删除最后一个char的项目完全相同)并将组合框内容更改为仅一个项目.这会导致调用,其中组合框使用当前的comboBox.getValue()字符串恢复编辑器值,从而产生没有任何反应的错觉.它还会导致第二次调用您的changed()方法,但此时编辑器文本已经更改.

Why do this only happen the first time,but then never again?

好问题!这只发生一次,因为您正在修改组合框的整个基础模型一次(如前所述,触发对changed()方法的第二次调用).

因此,如果您单击下拉按钮(右箭头),则在上一个场景发生后,您将看到只剩下一个项目,如果您再次尝试删除一个字符,则仍会保留相同的项目,即模型(组合框的内容没有改变,因为setPredicate()仍将匹配相同的内容,因此不会在TextInputControl类中引起markInvalid()调用,因为内容实际上没有改变,这意味着不再恢复项目字符串(如果要查看文本字段实际还原的位置,请第一次使用JavaFX源查看ComboBoxPopupControl.updateDisplayNode()方法).

If I select an item from the list,and then try to remove any other
character than the last,the whole string gets removed.

在你的第二个场景中,没有任何东西与第一个setPredicate()调用匹配(没有匹配你的startsWith条件的项目),这会删​​除组合框中删除当前选择和编辑器字符串的所有项目.

提示:尝试并自己理解这一点,在切换()方法内切换断点,以查看输入的次数和原因(如果您想要遵循ComboBox及其组件行为,则需要JavaFX源)

解:
如果你想继续使用你的ChangeListener,你可以通过在过滤后恢复编辑器中的文本来简单地攻击你的主要问题(这是在setPredicate调用之后被替换的编辑器内容):

class InputFilter implements ChangeListenerBoxBoxItem> Box;
    private FilteredListBoxItem> items;

    public InputFilter(ComboBoxBoxItem> Box,FilteredListBoxItem> items) {
        this.Box = Box;
        this.items = items;
    }

    @Override
    public void changed(ObservableValueBox.getSelectionModel().getSelectedItem() != null
                ? Box.getSelectionModel().getSelectedItem().getText() : null;

        // If an item is selected and the value of in the editor is the same
        // as the selected item we don't filter the list.
        if (selected != null && value.equals(selected)) {
            items.setPredicate(item -> {
                return true;
            });
        } else {
            // This will most likely change the Box editor contents
            items.setPredicate(item -> {
                if (item.getText().toUpperCase().startsWith(value.toUpperCase())) {
                    return true;
                } else {
                    return false;
                }
            });

            // Restore the original search text since it was changed
            Box.getEditor().setText(value);
        }

        //Box.show(); // <-- Uncomment this line for a neat look
    }
}

我个人以前在使用KeyEvent处理程序之前已经完成了这个(为了避免在changed()事件中多次调用我的代码),但是你总是可以使用semaphore或java.util.concurrent类中你喜欢的类来避免如果你觉得你开始需要它,任何不必要的重新进入你的方法.现在,getEditor().setText()将始终尾部恢复正确的值,即使相同的方法向下冒泡两到三次.

希望这可以帮助!

原文链接:https://www.f2er.com/java/437264.html

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