java – 如何对字符串进行排序,以便首先显示带有额外信息的值?

前端之家收集整理的这篇文章主要介绍了java – 如何对字符串进行排序,以便首先显示带有额外信息的值?前端之家小编觉得挺不错的,现在分享给大家,也给大家做个参考。
我试图排序以下字符串
1.0.0.0-00000000-00000
2.1.0.0
2.2.0.0
2.3.0.0-00000000-00000

我目前在一个字符串数组中有这些值.

String[] arrays = {"1.0.0.0-00000000-00000","2.1.0.0","2.2.0.0","2.3.0.0-00000000-00000"};

我试图有一个输出,如果没有“ – ”那么这些值按排序顺序到达我的数组的末尾.我想要输出如下:

1.0.0.0-00000000-00000
2.3.0.0-00000000-00000
2.1.0.0
2.2.0.0

我试过Arrays.sort(数组),但我不确定如何对它进行排序?

import java.util.Arrays;
import java.util.Comparator;
import java.util.Collections;

public class HelloWorld{

     public static void main(String []args){

       String[] arrays = {"1.0.0.0-00000000-00000","2.3.0.0-00000000-00000"};
       String[] newArray = new String[arrays.length];

    class CustomComparator implements Comparator<String>
    {
        @Override
        public int compare(String a,String b)
        {
            if(a.contains("-") && !b.contains("-"))
                 return 1;
            else if(!a.contains("-") && b.contains("-"))
                 return -1;
            return a.compareTo(b);
        }
    }

    Arrays.sort(arrays,new CustomComparator());

       for(String array : arrays)
       {
            System.out.println(array);
       }

     }
}


Error:

$javac HelloWorld.java 2>&1

HelloWorld.java:25: error: no suitable method found for sort(String[],CustomComparator)
    Collections.sort(arrays,new CustomComparator());
               ^
    method Collections.<T#1>sort(List<T#1>,Comparator<? super T#1>) is not applicable
      (no instance(s) of type variable(s) T#1 exist so that argument type String[] conforms to formal parameter type List<T#1>)
    method Collections.<T#2>sort(List<T#2>) is not applicable
      (cannot instantiate from arguments because actual and formal argument lists differ in length)
  where T#1,T#2 are type-variables:
    T#1 extends Object declared in method <T#1>sort(List<T#1>,Comparator<? super T#1>)
    T#2 extends Comparable<? super T#2> declared in method <T#2>sort(List<T#2>)
1 error



    The method gave me an output of 
2.1.0.0 
2.2.0.0
1.0.0.0-00000000-00000 
2.3.0.0-00000000-00000 

as opposed to

1.0.0.0-00000000-00000
2.3.0.0-00000000-00000
2.1.0.0 
2.2.0.0

解决方法

使用比较器
import java.util.Comparator;
    class CustomComparator implements Comparator<String> {
        @Override
        public int compare(String a,String b) {
            if(a.contains("-") && !b.contains("-"))
                 return 1;
            else if(!a.contains("-") && b.contains("-"))
                 return -1;
            return a.compareTo(b);
        }
    }
    Collections.sort(arrays,new CustomComparator());

返回负值表示b在a之前,而正值表示a在b之前

原文链接:https://www.f2er.com/java/130245.html

猜你在找的Java相关文章