我错过了什么吗?来源很短,随时可以运行和评论,以便更好地理解.我需要知道我做错了什么.
package com.company; import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.util.*; public class Main { public static ArrayList<Integer> randomArrayList(int n) { ArrayList<Integer> list = new ArrayList<>(); Random random = new Random(); for (int i = 0; i < n; i++) { list.add(random.nextInt(n)); } return list; } public static List<Integer> MergeSort(List<Integer> A) throws Exception{ if (A.size()==1) return A; int mid = A.size()/2; List<Integer> left = A.subList(0,mid); List<Integer> right = A.subList(mid,A.size()); left = MergeSort(left); right = MergeSort(right); A = Merge(left,right); return A; } public static List<Integer> Merge(List<Integer> L,List<Integer> R) throws Exception{ List<Integer> output = new ArrayList<Integer>(Collections.nCopies(L.size() + R.size(),0)); int i = 0; int j = 0; int k = 0; while (i < L.size() && j < R.size()) { if (L.get(i) < R.get(j)) { output.set(k,L.get(i)); i=i+1; } else { output.set(k,R.get(j)); j=j+1; } k++; } while (i < L.size()) { output.set(k,L.get(i)); i=i+1; k++; } while (j < R.size()) { output.set(k,R.get(j)); j=j+1; k++; } return output; } public static List<Integer> QuickSort(List<Integer> A) throws Exception{ if (A.size()==1 || A.size()==0) return A; //The pivot is a random element of the array A int randomIndex = new Random().nextInt(A.size()); Integer P = A.get(randomIndex); //Swap first element of A with selected pivot Integer tmp; A.set(randomIndex,A.get(0)); A.set(0,P); //Initiate i and l (partition analysis progress counters) int l = 0,i = l + 1,r = A.size(); for (int j = l + 1; j < r; j++ ){ if (A.get(j)< P ){ //Swap A[j] and A[i] tmp = A.get(j); A.set(j,A.get(i)); A.set(i,tmp); //Increase i by 1 (counting the pos of already partitioned) i = i + 1; } } //Swap A[l] (Pivot) and A[i-1] most left element bigger than pivot tmp = A.get(l); A.set(l,A.get(i-1)); A.set(i - 1,tmp); QuickSort(A.subList(0,i-1)); QuickSort(A.subList(i,A.size())); return A; }
在main函数中,我运行20次两种方法进行比较.您可以复制代码的两个部分并运行它
public static void main(String[] args) throws Exception{ long startTime,endTime,duration; //Compare 20 times QuickSort vs MergeSort for (int i=0;i<20;i++){ List<Integer> arreglo = randomArrayList(100000); startTime = System.nanoTime(); QuickSort(arreglo); endTime = System.nanoTime(); duration = (endTime - startTime)/1000000; System.out.println("Quicksort: " + Long.toString(duration)); startTime = System.nanoTime(); MergeSort(arreglo); endTime = System.nanoTime(); duration = (endTime - startTime)/1000000; System.out.println("MergeSort: "+Long.toString(duration)); //System.out.println(Arrays.toString(QuickSort(arreglo).toArray())); //System.out.println(Arrays.toString(MergeSort(arreglo).toArray())); } } }
@R_403_323@
这是我的评论作为答案:您正在对同一列表进行两次排序,因此第二种排序总是对已经排序的列表进行排序(这几乎总是与第一次排序的列表不同).
试试你的主要代码的这个变种:
public static void main(String[] args) throws Exception{ long startTime,duration; //Compare 20 times QuickSort vs MergeSort for (int i=0;i<20;i++){ List<Integer> arreglo = randomArrayList(100000); List<Integer> arreglo2 = new ArrayList<>(arreglo); // Make a copy startTime = System.nanoTime(); QuickSort(arreglo); // Sort the original endTime = System.nanoTime(); duration = (endTime - startTime)/1000000; System.out.println("Quicksort: " + Long.toString(duration)); startTime = System.nanoTime(); MergeSort(arreglo2); // Sort the copy endTime = System.nanoTime(); duration = (endTime - startTime)/1000000; System.out.println("MergeSort: "+Long.toString(duration)); } }