我试图在JRE 8中显示一个标签,说明所有内容都只有3秒,因为我无法在JRE 7中使用DatePicker而且我发现了这个错误.
Exception in thread "Timer-2" java.lang.IllegalStateException: Not on FX application thread; currentThread = Timer-2 at com.sun.javafx.tk.Toolkit.checkFxUserThread(Unknown Source) at com.sun.javafx.tk.quantum.QuantumToolkit.checkFxUserThread(Unknown Source) at javafx.scene.Scene.addToDirtyList(Unknown Source) at javafx.scene.Node.addToSceneDirtyList(Unknown Source) at javafx.scene.Node.impl_markDirty(Unknown Source) at javafx.scene.Node$7.invalidated(Unknown Source) at javafx.beans.property.BooleanPropertyBase.markInvalid(Unknown Source) at javafx.beans.property.BooleanPropertyBase.set(Unknown Source) at javafx.css.StyleableBooleanProperty.set(Unknown Source) at javafx.scene.Node.setVisible(Unknown Source) at Pantallas.PersonalContabilidad$1.run(PersonalContabilidad.java:221) at java.util.TimerThread.mainLoop(Unknown Source) at java.util.TimerThread.run(Unknown Source)
正确是一个标签,我显示3秒,它在correct.setVisible(false)失败;这是第221行
correct.setVisible(true);
timer.schedule(new TimerTask() {
@Override
public void run() {
correct.setVisible(false);
}
},3*1000);
解决方法
标签正确应该从FX应用程序线程更新.你应该在这里使用Platform.runLater().
correct.setVisible(true);
timer.schedule(new TimerTask() {
@Override
public void run() {
Platform.runLater(new Runnable() {
public void run() {
correct.setVisible(false);
}
});
}
},3*1000);
