java – 私有内部类的构造函数也是私有的吗?

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我正在重构一个正在变大的 android项目.运行lint为我提供了JSME问题外部和内部类之间的私有成员访问.考虑以下示例
public class Outer {
    private Inner mInner = new Inner();

    private class Inner {}
}

我得到的信息

Name
   privatefieldInnermInner

Location
   classOuter (default package)

Problem synopsis
   Access to private member of class 'Inner' at line 2

Problem resolution
   Make 'Inner' constructor package-local

应用问题解决方案会将源更改为

public class Outer {
    private Inner mInner = new Inner();

    private class Inner {
        Inner() {}
    }
}

我此刻有点困惑.到现在为止,我认为这个例子相当于

public class Outer {
    private Inner mInner = new Inner();

    private class Inner {
        public Inner() {}
    }
}

在这种情况下我错了还是皮棉问题?

解决方法

Section 8.8.9 of the Java language specification,“Default constructor”说:

In a class type,if the class is declared public,then the default constructor is implicitly given the access modifier public (§6.6); if the class is declared protected,then the default constructor is implicitly given the access modifier protected (§6.6); if the class is declared private,then the default constructor is implicitly given the access modifier private (§6.6); otherwise,the default constructor has the default access implied by no access modifier.

原文链接:https://www.f2er.com/java/128711.html

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