任何人都可以粘贴简单的步骤,将
Spring Security和CAS集成在这里,以进行单点登录和单点登录.
注意我不想要任何基于角色的访问.我有一个已经与弹簧安全集成的Web应用程序.现在我试图用CAS执行SSO,但是我收到这个错误sun.security.provider.certpath.SunCertPathBuilderException:无法找到有效的认证路径到请求的目标
注意我不想要任何基于角色的访问.我有一个已经与弹簧安全集成的Web应用程序.现在我试图用CAS执行SSO,但是我收到这个错误sun.security.provider.certpath.SunCertPathBuilderException:无法找到有效的认证路径到请求的目标
这是我当前的spring security.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:sec="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd "> <sec:http entry-point-ref="casProcessingFilterEntryPoint" > <sec:intercept-url pattern="/**" access="ROLE_USER" /> <sec:logout logout-success-url="/loggedout.jsp" invalidate-session="true"/> <sec:custom-filter ref="casAuthenticationFilter" after="CAS_FILTER"/> </sec:http> <sec:authentication-manager alias="authenticationManager"> <sec:authentication-provider ref="casAuthenticationProvider"/> </sec:authentication-manager> <bean id="casAuthenticationFilter" class="org.springframework.security.cas.web.CasAuthenticationFilter"> <property name="authenticationManager" ref="authenticationManager"/> <property name="authenticationFailureHandler"> <bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationFailureHandler"> <property name="defaultFailureUrl" value="/casFailed.jsp"/> </bean> </property> <property name="authenticationSuccessHandler"> <bean class="org.springframework.security.web.authentication.SimpleUrlAuthenticationSuccessHandler"> <property name="defaultTargetUrl" value="/"/> </bean> </property> </bean> <bean id="casProcessingFilterEntryPoint" class="org.springframework.security.cas.web.CasAuthenticationEntryPoint"> <property name="loginUrl" value="https://cegicollabdev.india.xxx.com:8443/cas/login"/> <property name="serviceProperties" ref="serviceProperties"/> </bean> <bean id="casAuthenticationProvider" class="org.springframework.security.cas.authentication.CasAuthenticationProvider"> <property name="userDetailsService" ref="userService"/> <property name="serviceProperties" ref="serviceProperties" /> <property name="ticketValidator"> <bean class="org.jasig.cas.client.validation.Cas20ServiceTicketValidator"> <constructor-arg index="0" value="https://cegicollabdev.india.tcs.com:8443/cas" /> </bean> </property> <property name="key" value="an_id_for_this_auth_provider_only"/> </bean> <bean id="serviceProperties" class="org.springframework.security.cas.ServiceProperties"> <property name="service" value="http://localhost:8080/dbcomparision/j_spring_cas_security_check"/> <property name="sendRenew" value="false"/> </bean> <bean id="userService" class="com.tcs.ceg.services.impl.UserServiceImpl" /> <!-- <sec:global-method-security pre-post-annotations="enabled" /> <sec:http pattern="/css/**" security="none"/> <sec:http pattern="/images/**" security="none"/> <sec:http pattern="/js/**" security="none"/> <sec:http pattern="/index.jsp" security="none"/> <sec:http pattern="/app/addNewUser.json" security="none"/> <sec:http pattern="/dbcomplogin.jsp" security="none"/> <sec:http pattern="/loggedout.jsp" security="none"/> <sec:http use-expressions="true">--> <!-- Allow all other requests. In a real application you should adopt a whitelisting approach where access is not allowed by default --> <!-- <sec:intercept-url pattern="/**" access="isAuthenticated()" /> <sec:form-login login-page='/dbcomplogin.jsp' authentication-failure-url="/dbcomplogin.jsp?login_error=1" default-target-url="/index.jsp" /> <sec:logout logout-success-url="/loggedout.jsp" delete-cookies="JSESSIONID"/> <sec:remember-me /> </sec:http> <bean id="myUserService" class="com.tcs.ceg.services.impl.UserServiceImpl" /> <sec:authentication-manager> <sec:authentication-provider user-service-ref="myUserService" /> </sec:authentication-manager> --> </beans>
这是我的web.xml
<?xml version="1.0" encoding="UTF-8"?> <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5"> <display-name>Spring3MVC</display-name> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/spring-rootcontext.xml /WEB-INF/spring-security.xml </param-value> </context-param> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <!-- - Loads the root application context of this web app at startup. --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>/app/*</url-pattern> </servlet-mapping> <filter> <filter-name>CAS Single Sign Out Filter</filter-name> <filter-class>org.jasig.cas.client.session.SingleSignOutFilter</filter-class> </filter> <filter-mapping> <filter-name>CAS Single Sign Out Filter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <listener> <listener-class>org.jasig.cas.client.session.SingleSignOutHttpSessionListener</listener-class> </listener> </web-app>
这是我的Spring-rootcontext.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:jee="http://www.springframework.org/schema/jee" xmlns:lang="http://www.springframework.org/schema/lang" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd" > <context:annotation-config /> <mvc:annotation-driven /> <context:component-scan base-package="com.tcs.ceg" /> <jee:jndi-lookup id="dataSource1" jndi-name="jdbc/PmdDS"/> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionfactorybean"> <property name="dataSource" ref="dataSource1" /> <property name="configLocation"> <value>classpath:hibernate.cfg.xml</value> </property> <property name="configurationClass"> <value>org.hibernate.cfg.AnnotationConfiguration</value> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.PostgresqlDialect</prop> <prop key="hibernate.show_sql">true</prop> <prop key="current_session_context_class">thread</prop> <prop key="cache.provider_class">org.hibernate.cache.NoCacheProvider</prop> <prop key="hibernate.connection.release_mode">auto</prop> </props> </property> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean> </beans>
这是我的spring-servlet.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xmlns:context="http://www.springframework.org/schema/context" xmlns:jee="http://www.springframework.org/schema/jee" xmlns:lang="http://www.springframework.org/schema/lang" xmlns:p="http://www.springframework.org/schema/p" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:util="http://www.springframework.org/schema/util" xmlns:mvc="http://www.springframework.org/schema/mvc" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd" > <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass"> <value> org.springframework.web.servlet.view.tiles2.TilesView </value> </property> </bean> <bean id="tilesConfigurer" class="org.springframework.web.servlet.view.tiles2.TilesConfigurer"> <property name="definitions"> <list> <value>/WEB-INF/tiles.xml</value> </list> </property> </bean> <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource"> <property name="basename" value="classpath:messages" /> <property name="defaultEncoding" value="UTF-8"/> </bean> <bean id="localeChangeInterceptor" class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor"> <property name="paramName" value="lang" /> </bean> <bean id="localeResolver" class="org.springframework.web.servlet.i18n.CookieLocaleResolver"> <property name="defaultLocale" value="en"/> </bean> <bean id="handlerMapping" class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping"> <property name="interceptors"> <ref bean="localeChangeInterceptor" /> </property> </bean> <bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver"> <!-- one of the properties available; the maximum file size in bytes --> <property name="maxUploadSize" value="1000000000000"/> </bean> </beans>
问题:1 sun.security.provider.certpath.SunCertPathBuilderException:无法找到有效的认证路径到请求的目标
问题3:这是否正确? < property name =“service”value =“http:// localhost:8080 / dbcomparision / j_spring_cas_security_check”/>,注意在我的程序中没有请求映射是j_spring_cas_security_check
解决方法
获取CAS认证工作的最简单的步骤是从Spring Security源代码树构建和运行
CAS sample.
在您尝试使用CAS之前,您需要了解CAS的工作原理,或将其与应用程序集成.我将从CAS文档和Spring Security参考手册中介绍interactions between CAS and Spring Security.
j_spring_cas_security_check是CAS对其进行身份验证后重定向到您的应用程序的URL(请参阅上述链接).
即使你的应用程序没有对用户进行身份验证,它仍然通常有一个它知道的用户的概念.它还必须加载这些用户的角色,CAS不能处理,因此用户服务声明.密码不会被使用.