我已经按照以下方式编写了一个方法：
if (something) {
return 1;
}
the rest of the code
在我看来,该方法返回1,然后执行其余的代码.真的可以吗不返回停止代码的执行.它不是,我如何强制一种方法停止？
这是代码(根据要求)：
for (int i=availableTime; i>0; i=i-1) {
final int sec = i;
SwingUtilities.invokeLater(new Runnable() {
public void run() {
String lbl = "<html>";
lbl += "</html>";
timeLeftLabel.setText(lbl);
}
});
try {Thread.sleep(1000);} catch (InterruptedException e) {}
parameterFromClientsListener = clientsListener.getValue(userName,parameterToGet);
if (!parameterFromClientsListener.equals("null")) {
output = parameterFromClientsListener;
game.log.fine(userName + " set (by button) " + parameterToGet + " to be equal to " + output + " . [IMPORTANT]");
return output;
}
}
game.log.fine("The partner selection phase is expired.");
// This code is executed if the Submit button was not pressed and the time run out.
if (parameterToGet.equals("partner")) {
tellMyChoice(parameterToGet,this.partnerFromForm,"timer of" + field);
output = this.partnerFromForm;
}
game.log.fine(parameterToGet + " was submitted by timer (not by OK button).");
} else {
output = parameterFromClientsListener;
}
game.log.fine(userName + " set (by timer)" + parameterToGet + " to be equal to " + output + " . [IMPORTANT]");
return output;
}
我运行这段代码两次.在每种情况下,我都会生成一个日志文件.在两个日志文件中,我看到“set(by button)”语句(在返回之前是直接的).但问题是在第二个日志文件中我看到“timer of”语句.如果达到“设定(按钮)”,则不能达到.怎么会这样？我需要提到的是,“set(by button)”和“timer”不会发生在我的代码中的任何地方(它们只发生一次).
添加3
从代码可以看出,我没有finally语句.
解决方法
这不是真的,return语句将停止任何以下代码. (唯一的例外是返回语句在try {}块中,后来有一个finally {}块.
if(0==0){
return;
}
System.out.println("This will not print.");
