[{
msg = "Hi This is Jecky";
name = Susheel;
sender = 77;
timestamp = 1464241769520;
username = susheel;
},{
msg = Dubai;
name = Jecky;
sender = 78;
timestamp = 1464246547147;
username = Jecky;
},{
msg = "How are you ?";
name = Susheel;
sender = 77;
timestamp = 1464243480381;
username = susheel;
},{
msg = "Aje dekhai nai";
name = Jecky;
sender = 78;
timestamp = 1464244974198;
username = Jecky;
}]
>我有这样的阵列.我想在swift 2.3或最新版本的swift中使用时间戳对这个数组进行排序.任何人都可以帮助我吗？
@H_502_6@解决方法
let array=[
[
"msg":"Hi This is Jecky","name":"Susheel","sender":77,"timestamp":1464241769520,"username":"susheel",],[
"msg":"Dubai","name":"Jecky","sender":78,"timestamp":1464246547147,"username":"Jecky",[
"msg":"How are you ?","timestamp":1464243480381,[
"msg":"Aje dekhai nai","timestamp":1464244974198,]
print("array = \(array)")
let sortedArray=array.sort { (obj1,obj2) -> Bool in
return (obj1["timestamp"] as! Double) < (obj2["timestamp"] as! Double)
}
print("sortedArray = \(sortedArray)")
@H_502_6@
@H_502_6@ 原文链接：https://www.f2er.com/iOS/332671.html