我有几个服务已经收到一个必须返回给客户端的json字符串(不是对象).目前,我正在显式创建HttpResponseMessage并将其Content属性设置为服务接收的json字符串：
var response = Request.CreateResponse(HttpStatusCode.OK); response.Content = new StringContent(jsonUtilizadores,Encoding.UTF8,"application/json"); return response;
现在,使用新的IHttpActionResult有更好的方法吗？使用Content或Ok方法最终用引号包装json字符串,这不是我想要的.
任何反馈？
解决方法
创建自定义实现.该框架可通过IHttpActionResult进行扩展.
public static class JsonStringResultExtension {
public static CustomJsonStringResult JsonString(this ApiController controller,string jsonContent,HttpStatusCode statusCode = HttpStatusCode.OK) {
var result = new CustomJsonStringResult(controller.Request,statusCode,jsonContent);
return result;
}
public class CustomJsonStringResult : IHttpActionResult {
private string json;
private HttpStatusCode statusCode;
private HttpRequestMessage request;
public CustomJsonStringResult(HttpRequestMessage httpRequestMessage,HttpStatusCode statusCode = HttpStatusCode.OK,string json = "") {
this.request = httpRequestMessage;
this.json = json;
this.statusCode = statusCode;
}
public Task<HttpResponseMessage> ExecuteAsync(CancellationToken cancellationToken) {
return Task.FromResult(Execute());
}
private HttpResponseMessage Execute() {
var response = request.CreateResponse(statusCode);
response.Content = new StringContent(json,"application/json");
return response;
}
}
}
…然后可以应用于ApiController派生类.大大简化以前的通话
return this.JsonString(jsonUtilizadores); //defaults to 200 OK
或者使用所需的HTTP状态代码
return this.JsonString(jsonUtilizadores,HttpStatusCode.BadRequest);
