刚刚开始我的第一次参加XPathNavigator.
这是我的简单xml：
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<theroot>
<thisnode>
<thiselement visible="true" dosomething="false"/>
<another closed node />
</thisnode>
</theroot>
现在,我使用CommonLibrary.NET库来帮助我一点：
public static XmlDocument theXML = XmlUtils.LoadXMLFromFile(PathToXMLFile);
const string thexpath = "/theroot/thisnode";
public static void test() {
XPathNavigator xpn = theXML.CreateNavigator();
xpn.Select(thexpath);
string thisstring = xpn.GetAttribute("visible","");
System.Windows.Forms.MessageBox.Show(thisstring);
}
问题是它无法找到属性.我已经查看了MSDN上的文档,但是无法理解正在发生的事情.
解决方法
这里有两个问题：
(1)您的路径是选择thisnode元素,但thiselement元素是具有属性和的元素
(2).Select()不会改变XPathNavigator的位置.它返回带有匹配项的XPathNodeIterator.
试试这个：
public static XmlDocument theXML = XmlUtils.LoadXMLFromFile(PathToXMLFile);
const string thexpath = "/theroot/thisnode/thiselement";
public static void test() {
XPathNavigator xpn = theXML.CreateNavigator();
XPathNavigator thisEl = xpn.SelectSingleNode(thexpath);
string thisstring = xpn.GetAttribute("visible","");
System.Windows.Forms.MessageBox.Show(thisstring);
}
