那么我试图创建一个小的应用程序,可以节省一些员工姓名,年龄和工资.所以我决定用Dictionary来设置每个员工的工资,我想出了这个代码
码
var employeeSalaryDictionary = new Dictionary<Employee,int>();
employeeSalaryDictionary.Add(new Employee { Name = "Chuck",Age = 37 },1000);
employeeSalaryDictionary.Add(new Employee { Name = "Norris",2000);
employeeSalaryDictionary.Add(new Employee { Name = "Rocks",Age = 44 },3000);
Employee employeeToFind = new Employee { Name = "Chuck",Age = 37 };
//or even
Employee employeeToFind = new Employee { Name = "Chuck"};
//Always False...
bool exists = employeeSalaryDictionary.ContainsKey(employeeToFind);
员工班
public class Employee
{
public string Name { get; set; }
public int Age { get; set; }
}
解决方法
您没有使用DictionaryqueryComparer< T>中的Dictionary构造函数.您也没有在Employee类上实现自定义的等式.
所以现在字典是通过参考比较员工.当你新的员工,你有一个不同的参考,即使例如名字可能是一样的
这可能是最简单的方式来实现自己的IEqualityComparer< Employee>,您可以在其中选择哪些成员将用于等式比较,并将其传递给字典的构造函数.
作为承诺,片段：
//ReSharper's courtesy
public sealed class NameAgeEqualityComparer : IEqualityComparer<Employee>
{
public bool Equals(Employee x,Employee y)
{
if (ReferenceEquals(x,y)) return true;
if (ReferenceEquals(x,null)) return false;
if (ReferenceEquals(y,null)) return false;
if (x.GetType() != y.GetType()) return false;
return string.Equals(x.Name,y.Name) && x.Age == y.Age;
}
public int GetHashCode(Employee obj)
{
unchecked
{
return ((obj.Name != null ? obj.Name.GetHashCode() : 0) * 397) ^ obj.Age;
}
}
}
接着：
var employeeSalaryDictionary = new Dictionary<Employee,int>(new NameAgeEqualityComparer());
employeeSalaryDictionary.Add(new Employee { Name = "Chuck",Age = 37 };
bool exists = employeeSalaryDictionary.ContainsKey(employeeToFind); // true!
为了完整性,这里是唯一的比较器(也是ReSharper的礼貌)：
public sealed class NameEqualityComparer : IEqualityComparer<Employee>
{
public bool Equals(Employee x,Employee y)
{
if (ReferenceEquals(x,y)) return true;
if (ReferenceEquals(x,null)) return false;
if (ReferenceEquals(y,null)) return false;
if (x.GetType() != y.GetType()) return false;
return string.Equals(x.Name,y.Name);
}
public int GetHashCode(Employee obj)
{
return (obj.Name != null ? obj.Name.GetHashCode() : 0);
}
}
但是,正如您所注意到的那样,您必须确定在创建字典时将使用哪个比较器进行键比较.以后不能改变…
