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我有一个类播放器,一些子类Player1,Player2,Player3使用C扩展播放器.
Class Player有一个方法“run”,所有Player1,2,3都会覆盖“run”来做不同的事情.
我有一个类播放器,一些子类Player1,Player2,Player3使用C扩展播放器.
Class Player有一个方法“run”,所有Player1,2,3都会覆盖“run”来做不同的事情.
class Player {
public:
virtual void run();
}
class Player1: public Player {
public:
void run();
}
在“main”函数中,我将创建一个Player1,3的实例
和一些C 11线程调用方法“运行”这些实例.
int main() {
Player1 player1;
Player2 player2;
Player3 player3;
Thread thread1(player1.run,this);
Thread thread2(player2.run,this);
Thread thread3(player3.run,this);
thread1.join();
thread2.join();
thread3.join();
return 0;
}
我试过,我知道它不起作用,
所以我尝试使用另一个函数来调用实例方法.
function doRun1(Player1 player){
player.run();
}
int main() {
Player1 player1;
Player2 player2;
Player3 player3;
Thread thread1(doRun1,player1);
Thread thread2(doRun2,player2);
Thread thread3(doRun3,player3);
thread1.join();
thread2.join();
thread3.join();
return 0;
}
这种方式似乎解决了问题,但我必须创建doRun1,doRun2,doRun3 ….很多功能,
因为doRun1,3的参数需要声明为Player1,2或3
我想不出更好的解决方案,有人可以帮助我@@？
解决方法
你正在寻找这样的东西……
class Player {
public:
virtual void run() = 0;
};
class Player1: public Player {
public:
void run(); // you must implement then for Player1,3
};
void doRun(Player * player)
{
player->run();
}
int main(int argc,char * argv[]) {
Player1 player1;
Player2 player2;
Player3 player3;
thread thread1(doRun,&player1);
thread thread2(doRun,&player2);
thread thread3(doRun,&player3);
thread1.join();
thread2.join();
thread3.join();
return 0;
}
如果您愿意,还可以使用lambda表达式：
int main(int argc,char * argv[]) {
Player1 player1;
Player2 player2;
Player3 player3;
thread thread1([&] (Player * player) { player->run(); },&player1);
thread thread2([&] (Player * player) { player->run(); },&player2);
thread thread3([&] (Player * player) { player->run(); },&player3);
thread1.join();
thread2.join();
thread3.join();
return 0;
}
或者,遵循DyP建议：
int main(int argc,char * argv[]) {
Player1 player1;
Player2 player2;
Player3 player3;
thread thread1(&Player::run,player1);
thread thread2(&Player::run,player2);
thread thread3(&Player::run,player3);
thread1.join();
thread2.join();
thread3.join();
return 0;
}
