我在下面的这个功能有问题：
char* GetPlayerNameEx(int playerid)
{
char Name[MAX_PLAYER_NAME],i = 0;
GetPlayerName(playerid,Name,sizeof(Name));
std::string pName (Name);
while(i == 0 || i != pName.npos)
{
if(i != 0) i++;
int Underscore = pName.find("_",i);
Name[Underscore] = ' ';
}
return Name;
}
宣言：
char* GetPlayerNameEx(int playerid);
用法：
sprintf(string,"%s",CPlayer::GetPlayerNameEx(playerid));
现在我的问题是
删除了个人信息.
如果这与我怀疑它有什么关系,那么这个函数包含在“Class”头(Declartion)中.
此外,我不知道为什么,但我不能让“代码”框正确适合.
解决方法
您不能将这些函数创建为静态(没有大量调整),因为您试图修改特定实例的数据.要解决您的问题：
class CPlayer
{
public:
// public members
// since you are operating on class member data,you cannot declare these as static
// if you wanted to declare them as static,you would need some way of getting an actual instance of CPlayer
char* GetPlayerNameEx(int playerId);
char* GetPlayerName(int playerId,char* name,int size);
private:
// note: using a std::string would be better
char m_Name[MAX_PLAYER_NAME];
};
// note: returning a string would be better here
char* CPlayer::GetPlayerNameEx(int playerId)
{
char* Name = new char[MAX_PLAYER_NAME];
memset(Name,MAX_PLAYER_NAME,0);
GetPlayerName(playerId,m_Name,sizeof(m_Name));
std::string sName(m_Name);
std::replace(sName.begin(),sName.end(),'_',' ');
::strncpy(sName.c_str(),MAX_PLAYER_NAME);
return Name;
}
// in your usage
CPlayer player;
// ...
sprintf(string,player.GetPlayerNameEx(playerid));
