我正在编写一个将Lua嵌入到C程序中的简单测试.
我在Windows / Mingw和Linux上遇到了同样的问题.
这是我在Linux上使用的gcc命令:
gcc -Wall -o test_lua lua_test.c -I/usr/include/lua5.1 -llua5.1
在Windows上:
gcc -Wall -o test_lua.exe lua_test.c -llua5.1
在这两种情况下,我都有以下警告:
warning: implicit declaration of function 'luaL_openlibs' [-Wimplicit-function-declaration]
该程序有效,但也许我不使用任何标准的Lua库?
为什么我会收到此警告?我在lauxlib.h中看到了luaL_openLibs的定义!
这是C部分:
#include <lua.h> #include <lauxlib.h> #include <stdlib.h> #include <stdio.h> int main(int argc,char *argv[]) { int status; lua_State *L; L = luaL_newstate(); // Init lua luaL_openlibs(L); // Load script status = luaL_loadfile(L,"lua_test.lua"); if (status) { fprintf(stderr,"Couldn't load file\n"); exit(1); } // Push data lua_pushnumber(L,5000); lua_setglobal(L,"clife"); lua_pushnumber(L,6000); lua_setglobal(L,"ttime"); lua_pushnumber(L,3000); lua_setglobal(L,"atime"); // Run script int result = lua_pcall(L,LUA_MULTRET,0); if (result) { fprintf(stderr,"Failed to run script: %s\n",lua_tostring(L,-1)); exit(1); } // Value at top of the stack is the result const char *schedule = lua_tostring(L,-1); fprintf(stdout,"Computed schedule is: %s\n",schedule); // Close lua lua_pop(L,1); lua_close(L); return 0; }
这是Lua部分:
io.write("lua_test.lua -- will generate schedule\n") io.write("Wizard life is " .. clife .. "\n") schedule = "" ctime = ttime - atime if clife > 4500 then schedule = schedule .. "[" .. ctime .. ",p]" schedule = schedule .. "[" .. ctime+500 .. ",a]" schedule = schedule .. "[" .. ctime+1000 .. ",i]" schedule = schedule .. "[" .. ctime+1500 .. ",n]\n" else schedule = schedule .. "[" .. ctime .. ",d]" schedule = schedule .. "[" .. ctime+500 .. ",r]" schedule = schedule .. "[" .. ctime+1000 .. ",a]" schedule = schedule .. "[" .. ctime+1500 .. ",n]\n" end io.write("Returning " .. schedule .. "\n"); return schedule
解决方法
AFAIK&在我的5.1.4安装中,该函数位于lualib.h中,而不是lauxlib.h中