error C2440: 'reinterpret_cast' : Pointers to members have different representations; cannot cast between them
这个东西告诉我,成员函数指针有不同的表示(doh!)
这些表示是什么?他们有什么区别?
解决方法
The Underlying Representation of Pointers to Members
Although pointers to members behave like ordinary pointers,behind the scenes their representation is quite different. In fact,a pointer to member usually consists of a struct containing up to four fields in certain cases. This is because pointers to members have to support not only ordinary member functions,but also virtual member functions,member functions of objects that have multiple base classes,and member functions of virtual base classes. Thus,the simplest member function can be represented as a set of two pointers: one holding the physical memory address of the member function,and a second pointer that holds the
this
pointer. However,in cases like a virtual member function,multiple inheritance and virtual inheritance,the pointer to member must store additional information. Therefore,you can’t cast pointers to members to ordinary pointers nor can you safely cast between pointers to members of different types.To get a notion of how your compiler represents pointers to members,use the
sizeof
operator. In the following example,the sizes of a pointer to data member and a pointer to a member function are taken. As you can see,they have different sizes,hence,different representations:
struct A { int x; void f(); }; int A::*pmi = &A::x; void (A::*pmf)() = &A::f; int n = sizeof (pmi); // 8 byte with my compiler int m = sizeof (pmf); // 12 bytes with my compiler
Note that each of these pointers may have a different representation,depending on the class in question and whether the member function is virtual.