#!/bin/sh i=1 while[$i-lt10];do j=1 while[$j-le$i];do echo-nx j=$(($j+1)) done echo i=$(($i+1)) done exit原文链接:https://www.f2er.com/bash/391238.html
#!/bin/sh i=1 while[$i-lt10];do j=1 while[$j-le$i];do echo-nx j=$(($j+1)) done echo i=$(($i+1)) done exit原文链接:https://www.f2er.com/bash/391238.html