写在前面:瑟瑟发抖的首次翻译
这是第一次动手翻译一篇外文,看懂和翻懂是不一样的,你所见到的是 v3.0 版本…
感谢 @依云 信雅达
的科普和满满的批注,还有依云和 @Tranch 传奇老师的最后的校正,以及,@Honwhy 的文章分享~
如果你发现本文有任何一处翻译不当的,欢迎指教,感谢感谢(///▽///)
译文开始
你所知的最简单的 Unix 命令是什么呢?
有echo
命令,用于将字符串打印到标准输出流,并以 o 为结束的命令。
在成堆的简单 Unix 命令中,也有 yes
命令。如果你不带参数地运行yes
命令,你会得到一串无尽的被换行符分隔开的 y 字符流:
y y y y (...你明白了吧)
一开始看似无意义的东西原来它是非常的有用:
yes | sh 糟心的安装.sh
你曾经有安装一个程序,需要你输入“y”并按下回车继续安装的经历吗?yes
命令就是你的救星。它会很好地履行安装程序继续执行的义务,而你可以继续观看 Pootie Tang.(一部歌舞喜剧)。
编写 yes
emmm,这是 BASIC 编写 ‘yes’的一个基础版本:
10 PRINT "y" 20 GOTO 10
下面这个是用 Python 实现的编写 ‘yes’:
while True: print("y")
看似很简单?不,执行速度没那么快!
事实证明,这个程序执行的速度非常慢。
python yes.py | pv -r > /dev/null [4.17MiB/s]
和我 Mac 自带的版本执行速度相比:
yes | pv -r > /dev/null [34.2MiB/s]
所以我重新写了一个执行速度更快的的 Rust 版本,这是我的第一次尝试:
use std::env; fn main() { let expletive = env::args().nth(1).unwrap_or("y".into()); loop { println!("{}",expletive); } }
解释一下:
- 循环里想打印的那个被叫做
expletive
字符串是第一个命令行的参数。expletive
这个词是我在yes
书册里学会的; - 用
unwrap_or
给expletive
传参,为了防止参数没有初始化,我们将yes
作为默认值 - 用
into()
方法将默认参数将从单个字符串转换为堆上的字符串
来,我们测试下效果:
cargo run --release | pv -r > /dev/null Compiling yes v0.1.0 Finished release [optimized] target(s) in 1.0 secs Running `target/release/yes` [2.35MiB/s]
emmm,速度上看上去并没有多大提升,它甚至比 Python 版本的运行速度更慢。这结果让我意外,于是我决定分析下用 C 实现的写入‘yes’程序的源代码。
这是 C 语言的第一个版本 ,这是 Ken Thompson 在 1979 年 1 月 10 日 Unix 第七版里的 C 实现的编写‘yes’程序:
main(argc,argv) char **argv; { for (;;) printf("%s\n",argc>1? argv[1]: "y"); }
这里没有魔法。
将它同 GitHub 上镜像的 GNU coreutils 的 128 行代码版 相比较,即使 25 年过去了,它依旧在发展更新。上一次的代码变动是在一年前,现在它执行速度快多啦:
# brew install coreutils gyes | pv -r > /dev/null [854MiB/s]
最后,重头戏来了:
/* Repeatedly output the buffer until there is a write error; then fail. */ while (full_write (STDOUT_FILENO,buf,bufused) == bufused) continue;
wow,让写入速度更快他们只是用了一个缓冲区。 常量BUFSIZ
用来表明这个缓冲区的大小,根据不同的操作系统会选择不同的缓冲区大小【写入/读取】操作高效(延伸阅读传送门 。我的系统的缓冲区大小是 1024 个字节,事实上,我用 8192 个字节能更高效。
好,来看看我改进的 Rust 新版本:
use std::io::{self,Write}; const BUFSIZE: usize = 8192; fn main() { let expletive = env::args().nth(1).unwrap_or("y".into()); let mut writer = BufWriter::with_capacity(BUFSIZE,io::stdout()); loop { writeln!(writer,"{}",expletive).unwrap(); } }
最关键的一点是,缓冲区的大小要是 4 的倍数以确保内存对齐 。
现在运行速度是 51.3MiB/s ,比我系统默认的版本执行速度快多了,但仍然比 Ken Thompson 在 [高效的输入输出] (https://www.gnu.org/software/... 文中说的 10.2GiB/s 慢。
更新
再一次,Rust 社区没让我失望。
这篇文章刚发布到 Reddit 的 Rust 板块, Reddit 的用户 nwydo 就提到了之前关于速率问题的讨论 。这个是先前讨论人员的优化代码,它打破了我机子的 3GB/s 的速度:
use std::env; use std::io::{self,Write}; use std::process; use std::borrow::Cow; use std::ffi::OsString; pub const BUFFER_CAPACITY: usize = 64 * 1024; pub fn to_bytes(os_str: OsString) -> Vec<u8> { use std::os::unix::ffi::OsStringExt; os_str.into_vec() } fn fill_up_buffer<'a>(buffer: &'a mut [u8],output: &'a [u8]) -> &'a [u8] { if output.len() > buffer.len() / 2 { return output; } let mut buffer_size = output.len(); buffer[..buffer_size].clone_from_slice(output); while buffer_size < buffer.len() / 2 { let (left,right) = buffer.split_at_mut(buffer_size); right[..buffer_size].clone_from_slice(left); buffer_size *= 2; } &buffer[..buffer_size] } fn write(output: &[u8]) { let stdout = io::stdout(); let mut locked = stdout.lock(); let mut buffer = [0u8; BUFFER_CAPACITY]; let filled = fill_up_buffer(&mut buffer,output); while locked.write_all(filled).is_ok() {} } fn main() { write(&env::args_os().nth(1).map(to_bytes).map_or( Cow::Borrowed( &b"y\n"[..],),|mut arg| { arg.push(b'\n'); Cow::Owned(arg) },)); process::exit(1); }
一个新的实现方式!
- 我们预先准备了一个填充好的字符串缓冲区,在每次循环中重用。
- 标准输出流被锁保护着,所以,我们不采用不断地获取、释放的形式,相反的,我们用 lock 进行数据写入同步。
- 我们用平台原生的 std::ffi::OsString 和 std::borrow::Cow 去避免不必要的空间分配
我唯一能做的事情就是 删除一个不必要的 mut 。
这是我这次经历的一个总结:
看似简单的 yes 程序其实没那么简单,它用了一个输出缓冲和内存对齐形式去提高性能。重新实现 Unix 工具很有意思,我很欣赏那些让电脑运行飞速的有趣的小技巧。
附上原文
A Little Story About the yes
Unix Command
What's the simplest Unix command you know?
There's echo
,which prints a string to stdout andtrue
,which always terminates with an exit code of 0.
Among the rows of simple Unix commands,there's alsoyes
. If you run it without arguments,you get an infinite stream of y's,separated by a newline:
y y y y (...you get the idea)
What seems to be pointless in the beginning turns out to be pretty helpful :
yes | sh boring_installation.sh
Ever installed a program,which required you to type "y" and hit enter to keep going?yes
to the rescue! It will carefully fulfill this duty,so you can keep watchingPootie Tang.
Writing yes
Here's a basic version in... uhm... BASIC.
10 PRINT "y" 20 GOTO 10
And here's the same thing in Python:
while True: print("y")
Simple,eh? Not so quick!
Turns out,that program is quite slow.
python yes.py | pv -r > /dev/null [4.17MiB/s]
Compare that with the built-in version on my Mac:
yes | pv -r > /dev/null
[34.2MiB/s]
So I tried to write a quicker version in Rust. Here's my first attempt:
use std::env; fn main() { let expletive = env::args().nth(1).unwrap_or("y".into()); loop { println!("{}",expletive); } }
Some explanations:
- The string we want to print in a loop is the first command line parameter and is named expletive. I learned this word from the yes manpage.
-
- use unwrap_or to get the expletive from the parameters. In case the parameter is not set,we use "y" as a default.
- The default parameter gets converted from a string slice (&str) into an owned string on the heap (String) using into().
Let's test it.
cargo run --release | pv -r > /dev/null Compiling yes v0.1.0 Finished release [optimized] target(s) in 1.0 secs Running `target/release/yes` [2.35MiB/s]
Whoops,that doesn't look any better. It's even slower than the Python version! That caught my attention,so I looked around for the source code of a C implementation.
Here's the very first version of the program,released with Version 7 Unix and famously authored by Ken Thompson on Jan 10,1979:
main(argc,argc>1? argv[1]: "y"); }
No magic here.
Compare that to the 128-line-version from the GNU coreutils,which is mirrored on Github. After 25 years,it is still under active development! The last code change happened around a year ago. That's quite fast:
# brew install coreutils gyes | pv -r > /dev/null [854MiB/s]
The important part is at the end:
/* Repeatedly output the buffer until there is a write error; then fail. */ while (full_write (STDOUT_FILENO,bufused) == bufused) continue;
Aha! So they simply use a buffer to make write operations faster. The buffer size is defined by a constant namedBUFSIZ
,which gets chosen on each system so as to make I/O efficient (see here). On my system,that was defined as 1024 bytes. I actually had better performance with 8192 bytes.
I've extended my Rust program:
use std::env; use std::io::{self,BufWriter,Write}; const BUFSIZE: usize = 8192; fn main() { let expletive = env::args().nth(1).unwrap_or("y".into()); let mut writer = BufWriter::with_capacity(BUFSIZE,io::stdout()); loop { writeln!(writer,expletive).unwrap(); } }
The important part is,that the buffer size is a multiple of four,to ensure memory alignment.
Running that gave me 51.3MiB/s. Faster than the version,which comes with my system,but still way slower than the results from this Reddit post that I found,where the author talks about 10.2GiB/s.
Update
Once again,the Rust community did not disappoint.
As soon as this post hit the Rust subreddit,user nwydo pointed out a previous discussion on the same topic. Here's their optimized code,that breaks the 3GB/s mark on my machine:
use std::env; use std::io::{self,)); process::exit(1); }
Now that's a whole different ballgame!
- We prepare a filled string buffer,which will be reused for each loop.
- Stdout is protected by a lock. So,instead of constantly acquiring and releasing it,we keep it all the time.
- We use a the platform-native
std::ffi::OsString
andstd::borrow::Cow
to avoid unnecessary allocations.
The only thing,that I could contribute was removing an unnecessary mut
. 原文链接:https://www.f2er.com/bash/389402.html