如何使用sudo执行bash函数？

我尝试导出该函数，然后使用bash执行，但这不起作用：

$ export -f my_func
$ sudo bash -c 'my_func' 
bash: my_func: command not found

如果我尝试使用没有sudo(bash -c’my_func’)的bash运行该函数，它将工作。

任何想法？

从 bmargulies的答案开始，我写了一个功能来解决这个问题，基本上实现了他的想法。

# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #
# EXESUDO
# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ #
#
# Purpose:
# -------------------------------------------------------------------- #
# Execute a function with sudo
#
# Params:
# -------------------------------------------------------------------- #
# $1:   string: name of the function to be executed with sudo
#
# Usage:
# -------------------------------------------------------------------- #
# exesudo "funcname" followed by any param
#
# -------------------------------------------------------------------- #
# Created 01 September 2012              Last Modified 02 September 2012

function exesudo ()
{
    ### ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##
    #
    # LOCAL VARIABLES:
    #
    ### ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##

    #
    # I use underscores to remember it's been passed
    local _funcname_="$1"

    local params=( "$@" )               ## array containing all params passed here
    local tmpfile="/dev/shm/$RANDOM"    ## temporary file
    local filecontent                   ## content of the temporary file
    local regex                         ## regular expression
    local func                          ## function source


    ### ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##
    #
    # MAIN CODE:
    #
    ### ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ##

    #
    # WORKING ON PARAMS:
    # ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

    #
    # Shift the first param (which is the name of the function)
    unset params[0]              ## remove first element
    # params=( "${params[@]}" )     ## repack array


    #
    # WORKING ON THE TEMPORARY FILE:
    # ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

    content="#!/bin/bash\n\n"

    #
    # Write the params array
    content="${content}params=(\n"

    regex="\s+"
    for param in "${params[@]}"
    do
        if [[ "$param" =~ $regex ]]
            then
                content="${content}\t\"${param}\"\n"
            else
                content="${content}\t${param}\n"
        fi
    done

    content="$content)\n"
    echo -e "$content" > "$tmpfile"

    #
    # Append the function source
    echo "#$( type "$_funcname_" )" >> "$tmpfile"

    #
    # Append the call to the function
    echo -e "\n$_funcname_ \"\${params[@]}\"\n" >> "$tmpfile"


    #
    # DONE: EXECUTE THE TEMPORARY FILE WITH SUDO
    # ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    sudo bash "$tmpfile"
    rm "$tmpfile"
}

使用示例：
运行以下代码段

#!/bin/bash

function exesudo ()
{
    # copy here the prevIoUs exesudo function !!!
}

test_it_out ()
{
    local params=( "$@" )
    echo "Hello "$( whoami )"!"
    echo "You passed the following params:"
    printf "%s\n" "${params[@]}" ## print array
}

echo "1. calling without sudo"
test_it_out "first" "second"

echo ""
echo "2. calling with sudo"
exesudo test_it_out -n "john done" -s "done"

exit

会输出

calling without sudo
Hello yourname!
You passed the following params:
first
second

calling with sudo
Hello root!
You passed the following params:
-n
john done
-s
foo

如果你需要在一个shell中调用一个bashrc中定义的函数，那么另外一个用户在serverfault上提到一个类似的问题，那么你必须将以前的exesudo函数放在同一个bashrc文件上，就像以下：

function yourfunc ()
{
echo "Hello "$( whoami )"!"
}
export -f yourfunc

function exesudo ()
{
   # copy here
}
export -f exesudo

然后你必须注销并重新登录或使用

source ~/.bashrc

最后你可以使用exesudo如下：

$ yourfunc
Hello yourname!

$ exesudo yourfunc
Hello root!

原文链接：https://www.f2er.com/bash/387465.html

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