我在目录中有几百gpg加密文件，格式为filename.xyz.gpg，其中“xyz”是一些任意扩展名。我需要解密所有的文件，以生成filename.xyz，这样我就不需要手动输入每个文件的密码。
我已经尝试了以下目录“测试”：
for file in 'ls Testing'; do (echo <password>|gpg --passphrase-fd 0 -d $file --output $file.decrypted);
我刚刚用命令提示符>结束，没有任何反应。
我的语法有什么问题？有没有一个更有效的方式来做这个没有bash shell循环？
正如手册中所说，您需要添加–batch选项：
原文链接：https://www.f2er.com/bash/387289.html--passphrase-fd n
Read the passphrase from file descriptor n. Only the first line will be read from file descriptor n. If you use 0 for n,the passphrase will be read from
STDIN. This can only be used if only one passphrase is supplied. Note that this passphrase is only used if the option --batch has also been given. This is
different from gpg.
--passphrase string
Use string as the passphrase. This can only be used if only one passphrase is supplied. ObvIoUsly,this is of very questionable security on a multi-user sys‐
tem. Don't use this option if you can avoid it. Note that this passphrase is only used if the option --batch has also been given. This is different from
gpg.
您可以使用以下两种形式之一：
echo "passphrase" | gpg --passphrase-fd 0 --batch -d --output "decrypted.file" "file.gpg"
或更简单：
gpg --passphrase "passphrase" --batch -d --output "decrypted.file" "file.gpg"
#!/bin/bash
read -rsp "Enter passphrase: " PASSPHRASE
for FILE in *.*.gpg; do
echo "Extracting $FILE to ${FILE%.gpg}."
echo "$PASSPHRASE" | gpg --passphrase-fd 0 --batch -d --output "${FILE%.gpg}" "$FILE"
done
