我使用
plupload版本1.3.0
更具体地说，我如何定义我的控制器动作来支持分块？可以使用HttpPosteFileBase作为参数吗？
在HEAD标签中
<link type="text/css" rel="Stylesheet" media="screen" href="<%: Url.Content( "~/_assets/css/plupload/jquery.ui.plupload.css" )%>" /> <link type="text/css" rel="Stylesheet" media="screen" href="<%: Url.Content( "~/_assets/css/plupload/gsl.plupload.css" )%>" /> <script type="text/javascript" src="<%: Url.Content( "~/_assets/js/plupload/gears_init.js" )%>"></script> <script type="text/javascript" src="<%: Url.Content( "~/_assets/js/plupload/plupload.full.min.js" )%>"></script> <script type="text/javascript" src="<%: Url.Content( "~/_assets/js/plupload/jquery.ui.plupload.min.js" )%>"></script>
文件准备好了
$("#uploader").pluploadQueue({
runtimes: 'html5,html4,gears,flash,silverlight',url: '<%: Url.Content( "~/Document/Upload" ) %>',max_file_size: '5mb',chunk_size: '1mb',unique_names: true,filters: [
{ title: "Documenti e Immagini",extensions: "doc,docx,xls,xlsx,pdf,jpg,png" }
],multiple_queues: false
});
解决方法
干得好：
[HttpPost]
public ActionResult Upload(int? chunk,string name)
{
var fileUpload = Request.Files[0];
var uploadPath = Server.MapPath("~/App_Data");
chunk = chunk ?? 0;
using (var fs = new FileStream(Path.Combine(uploadPath,name),chunk == 0 ? FileMode.Create : FileMode.Append))
{
var buffer = new byte[fileUpload.InputStream.Length];
fileUpload.InputStream.Read(buffer,buffer.Length);
fs.Write(buffer,buffer.Length);
}
return Content("chunk uploaded","text/plain");
}
对于每个块和正在上传的每个文件，此方法将被多次调用。它将作为参数传递块大小和文件名。我不确定您是否可以使用HttpPostedFileBase作为动作参数，因为名称不是确定性的。
