我已经设置了弹出窗口,但是我想把它放在按钮下面(View v)中,需要点击它来打开它：
public void showPopup(Context c,View v){
int[] location = new int[2];
v.getLocationOnScreen(location);
ViewGroup base = (ViewGroup) getView().findViewById(R.id.pup_pattern);
LayoutInflater inflater = (LayoutInflater) c.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View pupLayout = inflater.inflate(R.layout.linearlayout_popup,base);
final PopupWindow pup = new PopupWindow(pupLayout,android.view.ViewGroup.LayoutParams.WRAP_CONTENT,android.view.ViewGroup.LayoutParams.WRAP_CONTENT);
int x = location[0] - (int) ((pupLayout.getWidth() - v.getWidth()) / 2 ); // --> pupLayout.getWidth() gives back -2?
int y = location[1] + v.getHeight() + 10;
pup.setFocusable(true);
pup.showAtLocation(v,Gravity.NO_GRAVITY,x,y);
}
有人有办法采取措施吗？
解决方法
您不会得到视图的高度或宽度,该视图尚未在屏幕上绘制.
pupLayout.getWidth()//这将给你0
你需要得到这样的宽度
int width = MeasureSpec.makeMeasureSpec(0,MeasureSpec. UNSPECIFIED);
像这样使用它
View pupLayout = inflater.inflate(R.layout.linearlayout_popup,base); pupLayout.measure(MeasureSpec.makeMeasureSpec(0,MeasureSpec.UNSPECIFIED),MeasureSpec.makeMeasureSpec(0,MeasureSpec.UNSPECIFIED)); int x = location[0] - (int) ((pupLayout.getMeasuredWidth() - v.getWidth()) / 2 );
