我想从活动中开始一个广播接收者.我有一个Second.
java文件,它扩展了一个广播接收器和一个Main.java文件,我必须从中启动广播接收器.
我也尝试在Main.java中做的一切,如下,但不知道如何在清单文件中定义…
我也尝试在Main.java中做的一切,如下,但不知道如何在清单文件中定义…
Main.java：
public class Main extends Activity {
/** Called when the activity is first created. */
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
String rec_data = "Nothing Received";
private BroadcastReceiver myReceiver = new BroadcastReceiver() {
public void onReceive(Context context,Intent intent) {
// TODO Auto-generated method stub
if( intent.getStringExtra("send_data")!=null)
rec_data = intent.getStringExtra("send_data");
Log.d("Received Msg : ",rec_data);
}
};
}
protected void onResume() {
IntentFilter intentFilter = new IntentFilter();
//intentFilter.addDataType(String);
registerReceiver(myReceiver,intentFilter);
super.onResume();
}
@Override
protected void onPause() {
// TODO Auto-generated method stub
super.onPause();
this.unregisterReceiver(this.myReceiver);
}
}
如果我不能像上面那样在一个类中做任何事情,那我该如何从Main.java调用Broadcast Receiver？有谁能让我知道我在做错了什么？谢谢！
解决方法
使用这个为什么要发送自定义广播：
定义动作名称：
public static final String BROADCAST = "PACKAGE_NAME.android.action.broadcast";
AndroidManifest.xml注册接收器：
<receiver android:name=".myReceiver" >
<intent-filter >
<action android:name="PACKAGE_NAME.android.action.broadcast"/>
</intent-filter>
</receiver>
注册会员：
IntentFilter intentFilter = new IntentFilter(BROADCAST); registerReceiver( myReceiver,intentFilter);
从您的活动发送广播：
Intent intent = new Intent(BROADCAST);
Bundle extras = new Bundle();
extras.putString("send_data","test");
intent.putExtras(extras);
sendBroadcast(intent);
你的BroadcastReceiver：
private BroadcastReceiver myReceiver = new BroadcastReceiver() {
public void onReceive(Context context,Intent intent) {
// TODO Auto-generated method stub
Bundle extras = intent.getExtras();
if (extras != null){
{
rec_data = extras.getString("send_data");
Log.d("Received Msg : ",rec_data);
}
}
};
有关Custom Broadcast的更多信息,请参阅Custom Intents and Broadcasting with Receivers
