我在我的应用程序中有一个要求,我需要在应用程序中集成消息传递.我想使用
Android本机SMS API发送消息并接收它们.主要的挑战是我不想在消息应用程序中显示收到的消息.所有消息都应该打开,只能从应用程序发送.
我已经尝试在我的广播接收者接受以下意图：
<intent-filter>
<action android:name="android.provider.telephony.SMS_RECEIVED"></action>
</intent-filter>
但是当消息来到我的应用程序在同一个是由本机消息应用程序接收,我不想要.
我也尝试在模拟器的特定端口发送数据消息,它发送的是messgae,但是没有被我的应用程序接收,还有其他模拟器上的Message native应用程序.
意图过滤器是：
<intent-filter>
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
<data android:port="8901"/>
<data android:scheme="sms"/>
</intent-filter>
我使用给定端口的sendDataMessage()函数.
是否可能以更好和安全的方式发送消息,以便在Android中无法使用本机SMS API窃取您的数据？如果没有什么替代我可以去执行相同的.
解决方法
这是我实现的,它的工作就像我想要的那样.
private static final int MAX_SMS_MESSAGE_LENGTH = 160;
private static final int SMS_PORT = 8901;
private static final String SMS_DELIVERED = "SMS_DELIVERED";
private static final String SMS_SENT = "SMS_SENT";
private void sendSms(String phonenumber,String message) {
SmsManager manager = SmsManager.getDefault();
PendingIntent piSend = PendingIntent.getBroadcast(this,new Intent(SMS_SENT),0);
PendingIntent piDelivered = PendingIntent.getBroadcast(this,new Intent(SMS_DELIVERED),0);
byte[] data = new byte[message.length()];
for(int index=0; index<message.length() && index < MAX_SMS_MESSAGE_LENGTH; ++index)
{
data[index] = (byte)message.charAt(index);
}
manager.sendDataMessage(phonenumber,null,(short) SMS_PORT,data,piSend,piDelivered);
}
private BroadcastReceiver sendreceiver = new BroadcastReceiver()
{
@Override
public void onReceive(Context context,Intent intent)
{
String info = "Send information: ";
switch(getResultCode())
{
case Activity.RESULT_OK: info += "send successful"; break;
case SmsManager.RESULT_ERROR_GENERIC_FAILURE: info += "send Failed,generic failure"; break;
case SmsManager.RESULT_ERROR_NO_SERVICE: info += "send Failed,no service"; break;
case SmsManager.RESULT_ERROR_NULL_PDU: info += "send Failed,null pdu"; break;
case SmsManager.RESULT_ERROR_RAdio_OFF: info += "send Failed,radio is off"; break;
}
Toast.makeText(getBaseContext(),info,Toast.LENGTH_SHORT).show();
}
};
private BroadcastReceiver deliveredreceiver = new BroadcastReceiver()
{
@Override
public void onReceive(Context context,Intent intent)
{
String info = "Delivery information: ";
switch(getResultCode())
{
case Activity.RESULT_OK: info += "delivered"; break;
case Activity.RESULT_CANCELED: info += "not delivered"; break;
}
Toast.makeText(getBaseContext(),Toast.LENGTH_SHORT).show();
}
};
您的收件人的邮件应如下所示：
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.content.SharedPreferences;
import android.os.Bundle;
import android.preference.PreferenceManager;
import android.telephony.SmsMessage;
import android.text.TextUtils;
import android.util.Log;
import android.widget.Toast;
public class MySMSReceiver extends BroadcastReceiver {
String action,from,message;
@Override
public void onReceive(Context context,Intent intent) {
action=intent.getAction();
Bundle bundle = intent.getExtras();
SmsMessage[] msgs = null;
if(null != bundle)
{
String info = "Binary SMS from ";
Object[] pdus = (Object[]) bundle.get("pdus");
msgs = new SmsMessage[pdus.length];
byte[] data = null;
for (int i=0; i<msgs.length; i++){
msgs[i] = SmsMessage.createFromPdu((byte[])pdus[i]);
info += msgs[i].getOriginatingAddress();
info += "\n*****BINARY MESSAGE*****\n";
from= msgs[i].getOriginatingAddress();
data = msgs[i].getUserData();
for(int index=0; index<data.length; ++index) {
info += Character.toString((char)data[index]);
message += Character.toString((char)data[index]);
}
}
}
Intent showMessage=new Intent(context,AlertMessage.class);
showMessage.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
showMessage.putExtra("from",from);
showMessage.putExtra("message",message);
context.startActivity(showMessage);
}
}
我创建了一个简单的活动AlertMessage.java来显示收到的消息.
我在Manifest中注册我的广播接收器的方式：
<receiver android:name=".MySMSReceiver">
<intent-filter>
<action android:name="android.intent.action.DATA_SMS_RECEIVED" />
<data android:scheme="sms" />
<data android:port="8901" />
</intent-filter>
</receiver>
这里提到的端口必须与发送消息的sendSMS()方法中指定的端口相同.
更新：
Github工作项目库
