我只想创建一个这样的File对象
File my@L_404_0@File = new File(“image1”);
但它给我的FileNotFoundException异常
我如何在原始文件夹中引用一个文件
编辑：
其实我想做这样的事情
MultipartEntity multipartEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
multipartEntity.addPart(“uploaded”,new FileBody(new File(“myimage”)));
解决方法
这里有2个功能.一个从RAW读取,一个从资产中读取
/**
* Method to read in a text file placed in the res/raw directory of the
* application. The method reads in all lines of the file sequentially.
*/
public static void readRaw(Context ctx,int res_id) {
InputStream is = ctx.getResources().openRawResource(res_id);
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr,8192); // 2nd arg is buffer
// size
// More efficient (less readable) implementation of above is the
// composite expression
/*
* BufferedReader br = new BufferedReader(new InputStreamReader(
* this.getResources().openRawResource(R.raw.textfile)),8192);
*/
try {
String test;
while (true) {
test = br.readLine();
// readLine() returns null if no more lines in the file
if (test == null)
break;
}
isr.close();
is.close();
br.close();
} catch (IOException e) {
e.printStackTrace();
}
}
和Assets文件夹
/**
* Read a file from assets
*
* @return the string from assets
*/
public static String getQuestions(Context ctx,String file_name) {
AssetManager assetManager = ctx.getAssets();
ByteArrayOutputStream outputStream = null;
InputStream inputStream = null;
try {
inputStream = assetManager.open(file_name);
outputStream = new ByteArrayOutputStream();
byte buf[] = new byte[1024];
int len;
try {
while ((len = inputStream.read(buf)) != -1) {
outputStream.write(buf,len);
}
outputStream.close();
inputStream.close();
} catch (IOException e) {
}
} catch (IOException e) {
}
return outputStream.toString();
}
