AJAX showHint()函数

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data.PHP

<?PHP 
header("Content-type: text/html; charset=utf-8"); 
$val = $_GET['q'];
$regular = '/^[A-Z]/';
if (!preg_match($regular,$val)) {
	echo '用户名不合法';
}

 ?>


<html>
<head>
<script type="text/javascript">
function showHint(str)
{
var xmlhttp;
if (str.length==0)
  { 
  document.getElementById("txtHint").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+,Firefox,Chrome,Opera,Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6,IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","data.PHP?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>

<h3>请在下面的输入框中键入字母(A - Z):</h3>
<form action=""> 
<p>姓氏:<input type="text" id="txt1" onkeyup="showHint(this.value)" /><span id="txtHint"></span></p>
<input type="reset">
</form>
</body>
</html>

效果图:

原文链接:https://www.f2er.com/ajax/165171.html

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