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How do I return the response from an asynchronous call?16个答案我使用原型来做我的AJAX开发，我使用的代码如下：
somefunction: function(){
var result = "";
myAjax = new Ajax.Request(postUrl,{
method: 'post',postBody: postData,contentType: 'application/x-www-form-urlencoded',onComplete: function(transport){
if (200 == transport.status) {
result = transport.responseText;
}
}
});
return result;
}
我发现“结果”是一个空字符串。所以，我试过这：@H_502_4@
somefunction: function(){
var result = "";
myAjax = new Ajax.Request(postUrl,onComplete: function(transport){
if (200 == transport.status) {
result = transport.responseText;
return result;
}
}
});
}
记住onComplete是在someFunction完成工作后很久才调用的。你需要做的是将回调函数作为参数传递给some函数。当进程完成工作时(即onComplete)，将调用此函数：
原文链接：https://www.f2er.com/ajax/160697.htmlsomefunction: function(callback){
var result = "";
myAjax = new Ajax.Request(postUrl,onComplete: function(transport){
if (200 == transport.status) {
result = transport.responseText;
callback(result);
}
}
});
}
somefunction(function(result){
alert(result);
});
