我有这样的功能：
exports.saveAction = function (req,res) {
var conn = MysqL.createConnection({
host : nconf.get("database:host"),//port: 3306,user : nconf.get("database:username"),password : nconf.get("database:password"),database : nconf.get("database:database"),multipleStatements: true,//ssl: 'Amazon RDS'
});
var action = req.body;
conn.query('UPDATE actions SET ? WHERE Id = ?',[action,action.Id],function (err,result) {
conn.end();
if (err) throw err;
res.writeHead(200,{ "Content-Type": "application/json" });
res.end("Updated Successfully");
});
};
我返回“200”,但它总是返回错误子句如下所示：
$.ajax({
url: "/api/action/SaveAction",type: "PUT",data: ko.toJSON(self.stripDownObj()),datatype: "json",contentType: "application/json; charset=utf-8",success: function (result) {
console.log(result);
if(result.status == 200){
self.isEditMode(!self.isEditMode());
}
},error: function(result){
console.log(result);
}
});
注意：SQL查询是成功的,并且保存数据.
解决方法
当您期待JSON时返回JSON
res.end('{"success" : "Updated Successfully","status" : 200}');
接着
$.ajax({
....
datatype: "json",// expecting JSON to be returned
success: function (result) {
console.log(result);
if(result.status == 200){
self.isEditMode(!self.isEditMode());
}
},error: function(result){
console.log(result);
}
});
在Node中,您可以随时使用JSON.stringify获取有效的JSON
var response = {
status : 200,success : 'Updated Successfully'
}
res.end(JSON.stringify(response));
Express也支持做
res.json({success : "Updated Successfully",status : 200});
